Fc=mv2/r formula of centripetal force will be applied here with radius mass and velocity described in the above question
Answer:
1.) Longitudinal waves
2.) Transverse waves
3.) Longitudinal waves
Explanation:
The sound of one whale calling another whale underwater. is a longitudinal wave since the medium, in this case the body of water, is vibrating parallel to the direction of propagation of the wave.
A pulse sent down a stretched rope by snapping one end of it. ( transverse wave) because its oscillations are perpendicular to the direction of the wave or path of propagation
The vibrations in a guitar string
Longitudinal wave. Because its oscillations are parallel to the direction of the wave or path of propagation
Answer:
See explanation
Explanation:
We have a mass 
revolving around an axis with an angular speed 
, the distance from the axis is 
. We are given:
![\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]](https://tex.z-dn.net/?f=%5Comega%20%3D%2010%20%5Brad%2Fs%5D%5C%5Cr%3D0.5%20%5Bm%5D%5C%5Cm%3D13%5BKg%5D)
and also the formula which states that the kinetic rotational energy of a body is:
.
Now we use the kinetic energy formula
where 
is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:
After replacing in the previous equation we get:
now we have the following:
therefore:
then the moment of inertia will be:
![I = 13*(0.5)^2=3.25 [Kg*m^2]](https://tex.z-dn.net/?f=I%20%3D%2013%2A%280.5%29%5E2%3D3.25%20%5BKg%2Am%5E2%5D)
Answer:
Hz
Explanation:
We know that
1 cm = 0.01 m
= Length of the human ear canal = 2.5 cm = 0.025 m
= Speed of sound = 340 ms⁻¹
= First resonant frequency
The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as
for first resonant frequency, we have n = 1
Inserting the values
Hz
