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Zielflug [23.3K]
2 years ago
5

A football goalkeeper moves across her goal in a straight line. Her motion is shown on the following graph of horizontal positio

n xxx vs. time ttt. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. What is the average speed of the goalkeeper between the times t=4\text{ s}t=4 st, equals, 4, start text, space, s, end text and t=12\text{ s}t=12 st, equals, 12, start text, space, s, end text? Choose 1 answer: Choose 1 answer: (Choice A) A -0.25\,\dfrac{\text m}{\text s}−0.25 s m ​ minus, 0, point, 25, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice B) B 0.50\,\dfrac{\text m}{\text s}0.50 s m ​ 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice C) C -0.50\,\dfrac{\text m}{\text s}−0.50 s m ​ minus, 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice D) D 0.25\,\dfrac{\text m}{\text s}0.25 s m ​
Physics
1 answer:
sergejj [24]2 years ago
5 0

Answer:

0.25 m/s

Explanation:

Acceleration cannot be negative.

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8 0
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In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD 179949 (hence the
sp2606 [1]
  <span>I'll tell you how to do it but you must crunch the numbers. 

Use Kepler's 3rd Law 

T^2 = k R^3 

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6 0
2 years ago
A traffic light of weight 100 N is supported by two ropes that make 30-degree angle with the horizontal. What is the vertical co
alina1380 [7]

Answer:

T_{vertical} = 50 N

Explanation:

given,

traffic light weight = 100 N

angle at which the rope is supported = 30°

vertical component of force = ?

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T = \dfrac{100}{2 sin 30^0}

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3 years ago
The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed
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Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ \angle BCA = (90-30)

⇒             =60^{\circ}

then,

⇒ \angle BAC=(180-45-60)

⇒             =75^{\circ}

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The corresponding angle will be:

⇒ \angle FAC=60^{\circ}

⇒ \angle FAB=70+60

⇒             =135^{\circ}

Aspect of F across the AC arm will be:

= F\times cos(60)

On putting the values of F, we get

= 500\times (.5)

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Component F along the AC (in magnitude) will be:

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= 500\times (-.707)

= -353.5 \ N \

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Force = mass*acceleration so
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