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3 years ago

10

I am stuck on the before last question of this maths exam. I need reasoning for each answer and that is what I can't seem to get

.

1 answer:

sleet_krkn [62]3 years ago

7 0

Answer:

write this:

<BAC=x(alternate segment theorem)

<ABC=x

triangle ABC has 2 equal angles so it is an isosceles triangle.

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State the domain of the function<br> (-3,-1,1,2,4)<br> (-3,-1,1,2,3)<br> {0, 1,3,4,5)<br> {0, 1.4)

dmitriy555 [2]

Answer:

-4/4

Step-by-step explanation:

bc divison

3 0

3 years ago

What is the simplest form of 4/7+1/3=

Serggg [28]

Answer:

19/21 or .90

Step-by-step explanation:

Common denominator.

Multiply 4/7 by 3 which equals to 12/21

Multiply 1/3 by 7 which equals to 7/21

Add 12/21 and 7/21

Answer: 19/21

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2 years ago

If this is a 30° -60°-90° triangle, what are the lengths

Stels [109]

I have no idea but my best guess is 8: 4.3

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3 years ago

Your local radio station is having their yearly music player and concert ticket giveaway. For one minute, every 5^\text{th}5 th

kirza4 [7]

Answer:

<em>You were the 35th caller. </em>

Step-by-step explanation:

For one minute, every 5th caller will win a music player and every 7th caller will win concert tickets.

If you were just the first caller to win both a music player and concert tickets, that means <u>we need to find a least number which is divisible by both 5 and 7</u>.

<u>Actually we will find the LCM(Least common multiple) of 5 and 7</u>.

$5=1*5\\ \\ 7=1*7\\ \\ So, LCM = 1*5*7=35$

That means, you were the 35th caller.

6 0

3 years ago

Read 2 more answers

A car drives 12 miles north, turns, and then drives 8 miles east. How far is the car from its starting point?

Irina-Kira [14]

Draw a straight line. Label that 8. Perpendicular to that at one of the endpoints, draw a slightly smaller line. Label that 6. Draw another line from the end of 6 to the end of 8. This is x. To find how far the car went, we use the Pythagorean Theorem. a²+b²=c² so (8*8) + (6*6) = ? (64+36)=100 The square root of 100 is 10. The car is 10 miles away for the starting point.

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3 years ago