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xenn [34]
3 years ago
6

For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

k = 21

Step-by-step explanation:

xy = k\\\\Plugging\: x = 7\: and\: y = 3,\: we\; find:\\7\times 3 = k\\21 = k\\\huge\red{\boxed{k = 21}}\\

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Where: x is the raw score value, μ is the mean of the population, σ is the standard deviation of the population.

x = 80, μ = 5, σ = 4

z = (80 - 5) / 4

z = 75 / 4 = 18.7500

Z-score is 18.7500


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Find the lost common denominator of 3/4 and 5/8
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I assume you mean least. That would be 8.
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Question 9 of 10 If two triangles are congruent, which of the following statements must be true? Check all that apply. A. The tr
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Answer:

ACD

Step-by-step explanation:

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7 0
3 years ago
Mrs. Zarate is 4 feet 11 inches tall. If there are 2.54 centimeters
shusha [124]

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5 0
3 years ago
Read 2 more answers
Jeff is traveling from his home in Salem at a constant rate of 50 mph. He has already traveled 20 miles. His sister Jennifer is
leonid [27]

Answer    

Find out the  how long will it take Jennifer to catch Jeff.

To prove

Formula

Speed = \frac{Distance}{Time}

let us assume that the distance be denoted by d .

let us assume that the time be denoted by t .

As given

Jeff is traveling from his home in Salem at a constant rate of 50 mph.

He has already traveled 20 miles .

As put the values in the formula

50 = \frac{d + 20}{t}

50t - 20 = d

(As jeff already travelled 20 miles distance.)

As given

His sister Jennifer is making the same trip but at a constant rate of 60 mph and has only traveled 5 miles.

than put the value in the formula

60 = \frac{d +5}{t}

than the equation becomes

60t -5 = d

Than the two equation becomes

50t - 20 = d and 60t -5 = d

compare both the equation

50t - 20 = 60t -5

50t - 60t = 20 -5

- 10t = 15

t = \frac{-15}{10}

t = -1.5

(As time cannot be negative.)

t = 1.5 hours

1.5 hours will it take Jennifer to catch Jeff.

Option (A) is correct .







   

6 0
3 years ago
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