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3 years ago

When would you use the formula A= bh?

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

To get the area of a parallelogram

zloy xaker [14]3 years ago

4 0

Answer:

A. area of a parallelogram

Step-by-step explanation:

A = bh means area = base x height, which is the formula for the area of a parallelogram (or rectangle or square, which are special types of parallelogram).

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Use the function g(x)-x+2 with initial values of 4, 2, and 1. What happens

kolezko [41]

Answer:

Step-by-step explanation:

The given function is , g(x)= - x + 2

For values of , is the sequence, -2,4,-2,4,-2,4........

For values of , is the sequence, 0,2,0,2........

For values of , is the sequence, 1,1,1,1,........

For initial value, of 4,the sequence converges to two values that is -2, 4.

For initial value of 2, the sequence again converges to two values which are 0,2.

For initial value of 1, the sequence converges to one value which is 1.

→→First Iterative value that is (-2)=Second iterative value (0) + 2 ×Third iterative value(1)

→→ First Iterative value that is (4)=Second iterative value (2) + 2 ×Third iterative value(1)

4 0

3 years ago

Need some help...........

Anarel [89]

Answer:

The answer is to the question is 13

7 0

3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

3 years ago

After 8 points are added to each score in a sample, the mean is found to be M= 40. What was the value for the original mean

MArishka [77]

Answer:

The value for the original mean = 32

Step-by-step explanation:

Here, we want to calculate the original value of the mean.

Let the number of samples be n

Mathematically;

mean = Total value/n

Now, we added 8 to each of values; total value added = 8 * n = 8n

Now, for the new mean of 40; we have

(Total value + 8n)/n = 40

Total value + 8n = 40n

Total value = 40n -8n

Total value = 32n

kindly recall from the beginning of the solution;

mean = Total value/n

mean = 32n/n

mean = 32

So the original value of the mean is 32

6 0

3 years ago

Use I = PRT to solve.

Mice21 [21]

Answer:

Time T = 15 year

Step-by-step explanation:

Given:

Interest I = $270,000

Principal P = $150,000

Rate R = 12% = 0.12

Find:

Time T

Computation:

I = PRT

270,000 = (150,000)(0.12)(T)

270,000 = (18,000)(T)

Time T = 15 year

4 0

3 years ago