The base diameter and the height of a cone are both equal to x units. Which v expression represents the volume of the cone, in c
1 answer:
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Answer:
Ordering of objects from heaviest to lightest are ⇒ <u> school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.</u>
Step-by-step explanation:
Given:
School bus weight = 9 tons.
Horse = 1,100 pounds.
Elephant = 5,500 kilograms.
Grand piano = 15,840 ounces.
Now, order these objects from heaviest to lightest.
So, we need to take a common unit to order the items:
Thus, we take pounds as a common unit.
16 ounces = 1 pound.
1 kilogram = 2.2 pounds.
1 ton = 2,000 pounds.
Then, we calculate the weight of all items in pounds:
School bus 9 tons
Horse 1100 pounds
Elephant 5500 kilograms
Grand piano 15840 ounces
According to question:
Ordering from heaviest to lightest:
<em>School bus = 18000 pounds, elephant = 12100 pounds, horse = 1100 pounds and grand piano = 990 pounds.</em>
Therefore, ordering of objects from heaviest to lightest are ⇒ school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.
Answer:
Yes, a commute time between 10 and 11.8 minutes would be unusual.
Step-by-step explanation:
A probability is said to be unusual if it is lower than 5% of higher than 95%.
We use the normal probability distribution to solve this question.
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Would it be unusual for a commute time to be between 10 and 11.8 minutes?
The first step to solve this problem is finding the probability that the commute time is between 10 and 11.8 minutes. This is the pvalue of Z when subtracted by the pvalue of Z when X = 10. So
X = 11.8
has a pvalue of 0.0455
X = 10
has a pvalue of 0.0055
So there is a 0.0455 - 0.0055 = 0.04 = 4% probability that the commute time is between 10 and 11.8 minutes.
This probability is lower than 4%, which means that yes, it would be unusual for a commute time to be between 10 and 11.8 minutes.