All categories

3 years ago

What is the volume of the oblique cone? Round to the nearest tenth.

Mathematics

1 answer:

tino4ka555 [31]3 years ago

5 0

Answer:

Option (1). 142.4 cubic units

Step-by-step explanation:

The given question is incomplete: here is the complete question.

What is the volume of the oblique cone? Round to the nearest tenth.

142.4 cubic units

142.4 square units

196.0 cubic units

196.0 square units

Volume of n oblique cone is represented by the formula,

V = $\frac{1}{3}\times (\text{Area of the base})\times h$

From the figure attached,

Radius of the base = 4 units

Height of the cone = 8.5 units

Therefore, area of the base = πr²

= π(4)²

= 16π

Now volume of the cone = $\frac{1}{3}(16\pi )(8.5)$

= 142.4 cubic units

Therefore, Option (1) will be the answer.

You might be interested in

Help please soon !!!!!!

stepan [7]

75.25x + 3604 = 300.50x
300.50x - 75.25x = 3604
225.25x = 3604
x = 16
Both companies charged the same at 16 tons
first answer 16 tons
--------------------
300.50x = 300.50(16) = $4,808
both companies charged the same are $4,808
second answer is $4,808

5 0

3 years ago

Joe has 16 pounds of fertilizer for his three gardens. He uses 8/3 of the fertilizer in his first garden and 1/4 of the fertiliz

Natasha2012 [34]

Answer:

3/8

Step-by-step explanation:

3 0

3 years ago

Solve for x and y<br><br>6/x+2y + 5/x-2y = -3 ;<br>3/x+2y + 7/x-2y = -6

Radda [10]

Step-by-step explanation:

Let

{1/(x+2y)} = u -----Eqn(1)

{1/(x-2y)} = v ------Eqn(2)

So, given equation can be rewritten as

⇛6u + 5v = -3 ---Eqn(3)

⇛3u + 7v = -6 -----Eqn(4)

On multiply equation (4) by 2, we get

⇛6u + 14v = -12 -----Eqn(5)

On subtracting equation (3) from equation (5), we get

⇛9v = -9

⇛v = -9/9

⇛v = -1 ----Eqn(6)

Put value of v in equation (3), we get

6u + 5v = -3

⇛6u + 5 * (-1) = -3

⇛6u -5 = -3

⇛6u = -3 + 5

⇛6u = 2

⇛u = 2/6

⇛u = (2÷2)/(6÷2)

⇛u = 1/3 -----Eqn(7)

Now, substituting value of u and v in equation (1) and equation (2), we get

{1/(x+2y)} = 1/3 and {1/(x-2y)} = -1

⇛x + 2y = 3 -----Eqn(8)

⇛x - 2y = -1 -------Eqn(9)

Now, add equation (8) and equation (9) , we get

⇛2x = 2

⇛x = 2/2

On substituting x = 1 in equation (8), we get

x + 2y = 3

⇛ 1 + 2y = 3

⇛2y = 3 - 1

⇛2y = 2

⇛y = 2/2

Therefore, x = 1 and y = 1

<u>Answer</u><u>:</u> Hence the value of x and y is 1 and 1.

8 0

2 years ago

A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.

vichka [17]

Answer:

$14878.04878miles/hours^2$

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

$A=(Vf-Vi)/T$ where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

$A=(65miles/hour - 6miles/hour)/14.8seconds$ , but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

$X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)$

$X=0.0041hours$

Using X=0.0041hours in the previous equation instead of 14.8seconds we have:

$A=(65miles/hour - 6miles/hour)/0.0041hours$

$A=(61miles/hour)/0.0041hours$

$A=(61miles)/(hour*0.0041hours)$

$A=61miles/0.0041hours^2$

$A=14878.04878miles/hours^2$

In conclusion, the acceleration rate is $14878.04878miles/hours^2$

7 0

3 years ago

PLEASE HELP ALOT OF POINTSThe Pythagorean Theorem states "The square on the hypotenuse of a

mart [117]

Answer:

choice C. Yes, this image proves the pythagorean theorem is true because 9 + 16 = 25

Step-by-step explanation:

4 0

2 years ago