Answer:
The solution boils at 102.76 °C
Explanation:
Δt = m* Kb x i
i = 1 with 1 particle in solution
m = molality
Kb = 0.512 °C/molal
Step 2: Calculate moles C2H6O2
molar mass of C2H6O2 = 62.068 g/mol
Calculate number of moles:
Moles = Mass / molar mass
Moles = 1400 grams / 62.068 g/mol
Moles C2H6O2 = 22.56 moles
Step 3: Calculate molality
these are in 4192 g of water:
22.56 moles / 4.192 kg water
⇒ moles / kg of water = 5.38 moles / Kg = m
olal
Step 4: Calculate ΔT
ΔT= Kb * molal = 5.38 molal* 0.512 °C/m
ΔT = 2.76 °C
Boiling point = 100°C + 2.75 °C = 102.76 °C
the solution boils at 102.76 °C
