Chemical formula for Sn+4 O-2
1 answer:
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Answer:
Molarity of solution is 0.612 mol/L
Explanation:
Number of moles of a substance = (mass of substance)/(molar mass of the substance)
Molar mass of = 214 g/mol
So, 562 g of =
moles of
= 2.63 moles of
Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)
Here solute is and solvent is water
Total volume of solution is 4.30 L
So, molarity of solution =
= 0.612 mol/L
Answer:
freezing point (°C) of the solution = - 3.34° C
Explanation:
From the given information:
The freezing point (°C) of a solution can be prepared by using the formula:
where;
i = vant Hoff factor
the vant Hoff factor is the totality of the number of ions in the solution
Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3
= 1.86 °C/m
m = molality of the solution and it can be determined by using the formula
which can now be re-written as :
molality = 0.599 m
∴
The freezing point (°C) of a solution can be prepared by using the formula:
the freezing point of water - freezing point of the solution
3.34° C = 0° C - freezing point of the solution
freezing point (°C) of the solution = 0° C - 3.34° C
freezing point (°C) of the solution = - 3.34° C