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Goshia [24]
4 years ago
11

At 850 K, the equilibrium constant for the reaction

Chemistry
1 answer:
adell [148]4 years ago
8 0

Answer:

a) Q<Kc the reaction will shift to the right

b) Q=Kc the reaction is at the equilibrium

c) Q>Kc the reaction will shift to the left

Explanation:

Step 1: Data given

temperature = 850 K

Kc = 15

When Q=K, the system is at equilibrium. Since the system is already at equilibrium, there will no shift to left or right happen.

When Q>K, it means we have more products than reactants. As reaction, the amount of products will decrease, and produce more reactants. in other words, the reaction will shift to the left.

When Q<K, it means we have more reactants than products. As reaction, the amount of reactants will decrease, and will produce more products. In other words, the reaction will shift to the right.

Step 2: The balanced equation

2SO2(g)+O2(g)⇌2SO3(g) Kc=15

Step 3: Calculate Q

Q = [SO3]²/[O2][SO2]²

a. [SO2] = 0.60 M, [O2] = 0.70 M, [SO3] = 0.16 M

Q = 0.16²/0.70*0.60²

Q =0.10

Q << Kc

we have more reactants than products. As reaction, the amount of reactants will decrease, and will produce more products. In other words, the reaction will <u>shift to the right.</u>

<u />

b. [SO2] = 0.20 M, [O2] = 0.60 M, [SO3] = 0.60 M

Q = 0.60²/0.60*0.20²

Q = 15

Q=K, the system is at equilibrium. Since the system is already at equilibrium, there will no shift to left or right happen.

c. [SO2] = 0.10 M, [O2] = 0.20 M, [SO3] = 0.40 M

Q =  0.40²/0.20*0.10²

Q = 80

Q>K, it means we have more products than reactants. As reaction, the amount of products will decrease, and produce more reactants. in other words, the reaction will <u>shift to the left.</u>

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A 28.5 g piece of gold is heated and then allowed to cool. What is the change in temperature (°C) if the gold releases 0.106 kJ
Shkiper50 [21]

Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). It is calculated by the expression:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= 0.106 kJ= 106 J (being 1 kJ=1000 J)
  • c= 25.4 \frac{J}{molC}
  • m= 28.5 g×\frac{1 mole}{196.967 g} = 0.145 moles (being 196.967 g/mole the molar mass of gold)
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Replacing:

106 J= 25.4 \frac{J}{molC}× 0.145 moles× ΔT

Solving:

ΔT=\frac{106 J}{25.4\frac{J}{molC}x0.145 moles}

ΔT= 28.78 C

The change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

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