Photochemical smong result from the interaction of pollution in the presence of sunlight. The photochemical smog is result of the <span> chemical reaction in the air between the sunlight, nitrogen oxides and volatile organic compounds.
</span>It is noticed as a brown haze above cities. <span>The negative effects are: production of chlorofluorocarbons (CFCs) increased UV radiation, irritation to the eyes, nose, and throat. </span>
<h2>
Explanation:</h2><h3 /><h3>Oxygen- gains 2 electrons to form ions</h3><h3>Fluorine- gains 1 electron to form negative ions</h3><h3>Aluminum - loses three electrons to form ions</h3><h3>Calcium- loses 2 electrons in order to form ions</h3>
<h3>*Non metals gain electrons to form ions</h3><h3>*Metals loses electrons to form ions</h3>
<span>The correct answer is (C) 0.2 mole MgCl2.
according to Van't Hoff factor rule which is the ratio between the actual
concentration of the particles produced when the substance dissolved and
the concentration of the substance as measured from its mass, so here 0.2
mole MgCl2 is the higher van't Hoff factor as it has more ions than other
choices and the higher concentration.
and when the boiling point formula is delta Tb = Kb * m * i.
when delta Tb is the change in boiling point.
and Kb is molal boiling point constant
and m is the molality of the solution
and i is Van't Hoff factor.
so we can see the relationship between i and delta Tb, the greater Van't Hoff factor the higher the boiling point. so 0.2 MgCl2 is the higher boiling point as it is the greater van't Hoff factor.</span>
Answer:
B. High levels of nitrogen and phosphorus from agricultural runoff, sewage, and industrial pollution were flowing into the bay.
Explanation:
I just did this question! <3
The answer that best fits the blank provided above is the term GLUCOSE. The E<span>mbden-Meyerhof-Parnas pathway is a type of glycolysis, therefore, glucose is being converted in this process. Every mole of glucose is converted into two moles of pyruvic acid. Hope this helps.</span>
