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saw5 [17]
3 years ago
10

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer: (\frac{-5 +\sqrt{5}  }{2}, 0), (\frac{-5 -\sqrt{5}  }{2}, 0)

Step-by-step explanation: Let me know if you need an explanation.

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.<br> r = 9 sin 7θ
boyakko [2]

Answer:

The given function symmetric about the y-axis.

Step-by-step explanation:

The given function is

r=9\sin 7\theta                .... (1)

1. Symmetry about the x-axis: If the point (r, θ ) lies on the graph, then the point  (r,-θ ) or (-r, π - θ ) also lies on the graph.

2. Symmetry about the y-axis: If the point (r, θ ) lies on the graph, then the point (r,π - θ ) or (-r, -θ ) also lies on the graph.

3. Symmetry about the origin: If the point (r, θ ) lies on the graph, then the point (-r, θ ) or (r, π + θ ) also lies on the graph.

Put (r, -θ ) in the given function.

r=9\sin 7(-\theta)=-9\sin 7\theta=-r\neq r

Therefore it is not symmetric about x-axis.

Put (-r, -θ ) in the given function.

-r=9\sin 7(-\theta)=-9\sin 7\theta=-r

Therefore it is symmetric about y-axis.

Put (-r,θ ) in the given function.

-r=9\sin 7(\theta)=r\neq -r

Therefore it is not symmetric about the origin.

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3 years ago
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