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crimeas [40]
3 years ago
12

How many grams of h3po4 are in 521 ml of a 9.30 m solution of h3po4?

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0
V=521 ml = 0.521 L
c=9.30 mol/L
M(H₃PO₄)=98.00 g/mol

n(H₃PO₄)=cv
m(H₃PO₄)=n(H₃PO₄)M(H₃PO₄)=cvM(H₃PO₄)

m(H₃PO₄)=9.30*0.521*98.00=474.84 g

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what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​
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<h3>Answer:</h3>

1170.43 m³

<h3>Explanation:</h3>

<u>We are given;</u>

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  • Initial temperature, T1 as 585 K
  • Initial volume, V1 as 295 m³
  • New pressure, P2 as 102 kPa
  • New temperature, T2 as 293 K

We are required to find the new volume;

  • We are going to use the combined gas law
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V2=\frac{P1V1T2}{P2T1}

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