How many grams of h3po4 are in 521 ml of a 9.30 m solution of h3po4?

1 answer:

7 0

V=521 ml = 0.521 L
c=9.30 mol/L
M(H₃PO₄)=98.00 g/mol

n(H₃PO₄)=cv
m(H₃PO₄)=n(H₃PO₄)M(H₃PO₄)=cvM(H₃PO₄)

m(H₃PO₄)=9.30*0.521*98.00=474.84 g

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Classify each of the four compounds as a conjugated, isolated, or cumulated diene. Compound A: Two alkenes are joined by a sigma

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Explanation:

Conjugated diene is the one that contains alternate double bonds in its structure. That means both the double bonds are separated by a single bond.

Cumulated diene is the one that contains two double bonds on a single atom. This means it has two double bonds continuously.

Isolated double-bonded compound has a single bond isolated by two to three single bonds.

Compound A: Two alkenes are joined by a sigma bond.

For example:

$-CH_2=CH-CH=CH2-$

It is a conjugated diene.

Compound B: Two alkenes are joined by a C H 2 group.

It is a cumulative diene.

Compound C: Two alkenes are joined by C H 2 C H 2.

Then it is an isolated alkene.

Compound D: A cyclohexene has a double bond between carbons 1 and 2. Carbon 3 is an sp 2 carbon that is bonded to another s p 2 carbon with an alkyl substituent.

Hence, compound D is a conjugated diene.