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crimeas [40]
3 years ago
12

How many grams of h3po4 are in 521 ml of a 9.30 m solution of h3po4?

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0
V=521 ml = 0.521 L
c=9.30 mol/L
M(H₃PO₄)=98.00 g/mol

n(H₃PO₄)=cv
m(H₃PO₄)=n(H₃PO₄)M(H₃PO₄)=cvM(H₃PO₄)

m(H₃PO₄)=9.30*0.521*98.00=474.84 g

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Answer:

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Explanation:

The computation of the mass is shown below:

As we know that

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3 0
3 years ago
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8 0
3 years ago
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Answer:

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3 0
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