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bazaltina [42]
2 years ago
15

When there is a chemical reaction between hydrochloric acid and potassium hydroxide. Which substances are the reactants? Which s

ubstances are the product?
Chemistry
2 answers:
Aliun [14]2 years ago
6 0

Answer:

The reaction of acids and bases and what ions are produced and the salts that form. ... Pure water is an example of a neutral substance. ... Q: If you were to combine acid and base solutions, what products do you think would be produced? ... between solutions of hydrochloric acid and sodium hydroxide.

Explanation:

Tasya [4]2 years ago
3 0

Answer:

Good question i really dont know sorry

Explanation:

jhjhhshhjjjh

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What is the density of a liquid if it has a mass of 12.9g ?
user100 [1]
Find it on google i’m pretty sure i saw it somewhere so sorry this doesn’t help
4 0
3 years ago
When metals form ions, they tend to do so by what
In-s [12.5K]
Losing electrons and forming positive ions
5 0
3 years ago
Read 2 more answers
Which of the following best describes the difference in bonding between two hydrogen atoms and two carbon atoms?
valentinak56 [21]

Answer :

2. Hydrogen forms bonds through the overlap of 1s atomic orbitals and the sharing of electrons between atoms. Carbon forms bonds through the overlapping of sp hybrid atomic orbitals and the sharing of electrons between carbon atoms.

Explanation:

The H-H bond is formed by the overlap of two 1s orbitals and the sharing of electrons between the two atoms.

A carbon atom must use the overlap of hybridized atomic orbitals and the sharing of electrons to bond with another carbon atoms.

1. is <em>wrong</em> because H can use only its <em>1s orbital</em> for bonding.

3. is <em>wrong</em> because C must <em>share electrons</em> to form a carbon-carbon bond.

4. is <em>wrong</em> because <em>C does NOT use overlapping of 2s orbitals</em> for bonding. It uses the overlap of hybridized orbitals.

5. is <em>wrong</em> because H must <em>share electrons</em> to form an H-H bond.

4 0
3 years ago
A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t
Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

6 0
3 years ago
Photosynthesis by land plants leads to the fixation each year of about 1 kg of carbon on the average for each square meter of an
Rama09 [41]

Answer:

a) mass of carbon directly above 1 ( each)  square meter of the earth is 1.65kg

b) all CO₂ will definitely be used up from the atmosphere directly above a forest in 1.65 years

Explanation:

first we calculate the moles of carbon

moles = mass/molar mass

= 1kg/12gmol⁻¹

= 1000g/12gmol⁻¹

= 83.33 mol

now using the ideal gas equation

we find the volume of co₂required based on 83.33 moles

PVco₂ = nRT

Vco₂ = nRT/P

Vco₂ = (83.22mol × 0.0821L atm k⁻¹ mol⁻¹ 298 K) / 1 atm

Vco₂ = 2083.73 L

so since CO₂ in air is 0.0390% by volume in the atmosphere, we find the the total amount of air required to obtain 1kg carbon

therefore

Vair × 0.0390/100 = 2038.73L

Vair = (2038.73L × 100) / 0.0390

Vair = 5.23 × 10⁶L

therefore 5.23 × 10⁶ L of air will be required to obtain 1kg carbon

a)

Here we calculate the mass of air over 1 square meter of surface.

Remember that atmospheric pressure is the consequence of the force exerted by all the air above the surface; 1 bar is equivalent to 1.020×10⁴kgm⁻²

NOW

mass of air = 1.020×10⁴kgm⁻² × 1m²

= 1.020×10⁴kg

= 1.020×10⁷g    [1kg = 10³g]

we now find the moles of air associated with it

moles = mass/molar mass

= 1.020 × 10⁷g / ( 20%×Mo₂ + 80%×Mn₂)

= 1.020 × 10⁷g / ( 20%×32gmol⁻¹ + 80%×28gmol⁻¹)

= 1.020 × 10⁷g / 28.8 gmol⁻¹

= 354166.67mol

so based on the question, for each mole (air), there is 0.0390% of CO₂

now to calculate the moles of CO₂ we say;

MolesCo₂ = 0.0390/100 × 354166.67mol

= 138.125 moles

Now we calculate mass of CO₂ from the above findings

Moles = mass/molar mass

mass = moles × molar mass

= 138.125 moles × 12gmol⁻¹

= 1657.5g

we covert to KG

= 1657.5g / 1000

mass = 1.65kg

therfore mass of carbon directly above 1 ( each)  square meter of the earth is 1.65kg

b)

to find the number years required to use up all the CO₂, WE SAY

Number of years = total carbon per m² of the forest / carbon used up per m² from the forest per year

Number of years = 1.65kgm⁻² / 1kg²year⁻¹

Number of years = 1.65 years

Therefore all CO₂ will definitely be used up from the atmosphere directly above a forest in 1.65 years

6 0
3 years ago
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