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Taya2010 [7]
3 years ago
5

Jade spent ⅓ of her math homework time working on word problems. What fraction of an hour did she spend working on word problems

?
Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

If total maths hw time = 90 minutes, time spent on word problems = 1/2 hour

Step-by-step explanation:

Let the time available for maths homework be = 90 minutes. It is equal to 1.5 hour (as 1 hour = 60 minutes, 0.5 hour = 30 minutes).

1/3rd of maths homework time, ie 1/3rd of 90 minutes = 30 minutes, is used in doing word problems. These 30 minutes correspond to half (1/2 or 0.5) of an hour, as 1 hour = 30 minutes.

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Circle the division problem that does not belong with the other three. Explain 621/6 384/3 719/7 514/5
dsp73
384/3. because it comes out even..128..the rest won't
8 0
3 years ago
Given p(x)= 3x+1 and r(x)= 2x^2+5 which of the following represents the composition p(r(x)) ?
Temka [501]

Step-by-step explanation:

substitute the values

px=3x+1

=(3x+1)/x

=3x/x +1/x

=3+1/x

rx=2x²+5

p(r(x)) =(3+1/x(2x²+5))

=6x²+15+2x²/x+5/x

=3(2x²+5)+1/x(2x²+5)

=(2x²+5)(3+1/x)

6 0
3 years ago
What is the inverse of the function f(x) = 4x + 8?
morpeh [17]

Answer:

(A) h(x) = 1/4x -2

Step-by-step explanation:

Given: f(x)=4x+8

Rewrite with y: y=4x+8

Switch x and y: x=4y+8

Solve for y: x-8=4y

(x-8)/4=y

1/4x-2=y

y=1/4x-2

This means that h(x) = 1/4x -2 is the correct answer

8 0
3 years ago
PLEASE HURRY!! <br> simplify completely<br> show all work for full credit
Irina18 [472]

Answer:

4x^{3}

Step-by-step explanation:

<u>Given:</u>

(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}

<u>Apply exponent rule of distribution:</u>

\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the numerator:</u>

\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the denominator:</u>

\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}

<u>Simplify:</u>

4x^{3}

-> To explain this party since it is a bigger jump, 3^{\frac{1}{3}}x is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have x^{3} leftover too.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
3 years ago
There are 270 students at Colfax Middle School, where the ratio of boys to girls is 5:4. There are 180 students at Winthrop Midd
zavuch27 [327]

Given:

Total number of students at Colfax Middle School = 270

Ratio of boys to girls is 5:4.

Total number of students at Winthrop Middle School = 180

Ratio of boys to girls is 4:5.

The two schools hold a dance and all students from both schools attend.

To find:

The fraction of the students at the dance are girls

Solution:

There are 270 students at Colfax Middle School, where the ratio of boys to girls is 5:4.

5+4=9

Number of boys =270\times \dfrac{5}{9}=150

Number of girls =270\times \dfrac{4}{9}=120

There are 180 students at Winthrop Middle School, where the ratio of boys to girls is 4:5.

4+5=9

Number of boys =180\times \dfrac{4}{9}=80

Number of girls =180\times \dfrac{5}{9}=100

Now,

Total number of students in both schools = 270+180

                                                                = 450

Total number of girls in both schools = 120+100

                                                         = 220

The fraction of the students at the dance are girls is

\text{Required fraction}=\dfrac{\text{Total number of girls in both schools}}{\text{Total number of students in both schools}}

\text{Required fraction}=\dfrac{220}{450}

\text{Required fraction}=\dfrac{22}{45}

Therefore, the required fraction is \dfrac{22}{45}.                                

7 0
3 years ago
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