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andreev551 [17]
3 years ago
13

In 1903, Aegidius Elling of Norway designed and built an 11-hp gas turbine that used steam injection between the combustion cham

ber and the turbine to cool the combustion gases to a safe temperature for the materials available at the time. Currently, there are several gas-turbine power plants that use steam injection. Does steam injection improve the thermal efficiency of a gas-turbine power plant?
Engineering
1 answer:
solong [7]3 years ago
3 0

Answer:

Steam injection increases the mass flow rate of steam in the turbine. As a result, the power output from the turbine also increases.

Explanation:

Steam injection increases the mass flow rate of steam in the turbine. As a result, the power output from the turbine also increases.

Thermal efficiency increases as work output increases but heat addition remains constant. The process of steam injection is similar to the regeneration process. The exhaust gases which are coming from the exit of the turbine can be used to obtain steam.

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Liquid ethanol (C2H5OH) at 298 K, 1 atm enters a steam generator operating at steady state and burns completely with dry air ent
Gennadij [26K]

Answer:

Q= 6491.100 kJ/s

Explanation:

Air-Fuel Ratio:

For a combustion reaction the proportion of air that is present in a gaseous substance responsible for the reaction,this proportion is known as air-fuel ratio.The air fuel ratio is calculated using the combustion reaction for the substance.

Considering reaction for the Ethanol as

C₂H₅OH +XO₂(O₂+3.76N₂)→ aCO₂+bH₂O+cN₂

Balancing the equation we get;

a=2,

2b=6

∴ b=3

xO₂=3

The air-fuel ratio

A/F = XO₂+H₂O+xN₂× mass of N₂/mass(fuel)

3.31×31.9+11.28×28.013/46.069

= 8.943

Equivalent ratio = 0.7,

so, heat transfer

Q= m ×Cp×ΔT

= 75×0.7×112.4(1500-400)

Q= 6491.100 kJ/s

1kJ/s=1000w

∴ Q= 6491100 W

<u />

6 0
4 years ago
I need help on what’s and input and output to make the flowchart
e-lub [12.9K]

Input: what is put in, taken in, or operated on by any process or system.

Output: the amount of something produced by a person, machine, or industry.

3 0
3 years ago
Suppose there are 76 packets entering a queue at the same time. Each packet is of size 5 MiB. The link transmission rate is 2.1
tia_tia [17]

Answer:

938.7 milliseconds

Explanation:

Since the transmission rate is in bits, we will need to convert the packet size to Bits.

1 bytes = 8 bits

1 MiB = 2^20 bytes = 8 × 2^20 bits

5 MiB = 5 × 8 × 2^20 bits.

The formula for queueing delay of <em>n-th</em> packet is :  (n - 1) × L/R

where L :  packet size = 5 × 8 × 2^20 bits, n: packet number = 48 and R : transmission rate =  2.1 Gbps = 2.1 × 10^9 bits per second.

Therefore queueing delay for 48th packet = ( (48-1) ×5 × 8 × 2^20)/2.1 × 10^9

queueing delay for 48th packet = (47 ×40× 2^20)/2.1 × 10^9

queueing delay for 48th packet = 0.938725181 seconds

queueing delay for 48th packet = 938.725181 milliseconds = 938.7 milliseconds

4 0
3 years ago
technician a says that a gasoline engine is designed to operate at near or maximum speed for long periods without damage. techni
Vinil7 [7]

we can see that the correct person here will be Technician B who says that a diesel engine is designed to operate at near or maximum speed for long periods without damage.

<h3>What is a diesel engine?</h3>

A diesel engine is actually known to be an engine that makes use of diesel as its fuel. In other words, diesel engines run on diesel.

We see here that a diesel engine is actually designed to work for a very time on near or maximum speed without damage. This is true because the diesel fuel has that strength.

Also, diesel engines may be designed as two or four stroke cycles.

Learn more about diesel engine on brainly.com/question/13146091

#SPJ1

3 0
2 years ago
Three masses are attached to a uniform meter stick, as shown in Figure 12.9. The mass of the meter
sp2606 [1]

At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero

The mass of that balances the system is \underline {316.\overline 6} kg

The normal reaction force at the fulcrum is <u>5,804.25 N</u>

Rason:

The mass of the stick = 150.0 g

Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂

Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum

Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum

Required:

To find the mass of m₃

Solution:

Taking moment about the fulcrum, we have;

50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30

9,500 = m₃×30

m_3 = \dfrac{9,500}{30} = 316. \overline 6

The mass of that balances the system when it is attached at the right end of the stick, m₃ = 316.\overline 6 kg

Normal reaction at the fulcrum = (50 + 75 + 150 +  316.\overline 6) × 9.81 = 5804.25

The normal reaction at the fulcrum is 5,804.25 N

Learn more about the moment of a force here:

brainly.com/question/19464450

8 0
2 years ago
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