Answer:
a. 2.9218x10^(-29) m^3
b. 7.1230x10^(28) atoms/m^3
c. 2.0812 BM/atom
Explanation:
Atomic radius r = 0.154 nm
saturation flux density Bs = 0.83 tesla
- the formula for the volume of the simple cubic crystal (Vc) = a^3 = (2r)^3
= (2 x 0.154x10^-9)^3
= 2.9218x10^-29 m^3
- The formula for the Bohr magneton per atom with respect to VC, Bs, permeability of the vacuum Uo and magnetic moment per Bohr magneton Ub is;
Bohr magneton per atom nb = (Bs x VC) / (Ub x Uo)
= (0.83 x 2.9218x10^-29) / (9.27x10^-24) x(1.257x10^-6)
= 2.4251x10^-29 / 1.1652x10^-29
= 2.0812 BM/atom
- Number of atoms per Vc, N = nb / Vc
= 2.0812 / 2.9218x10^-29 = 7.1230x10^28 atoms
Answer:
yes
Explanation:
The 1991 standard states, "engineering and work practice controls shall be used to eliminate or minimize employee exposure." The revision defines Engineering Controls as "controls (e.g., sharps disposal containers, self-sheathing needles, safer medical devices, such as sharps with engineered sharps injury protections ...
Answer:
For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:
1. Using the Rise and Fall Method, find the reduced level for all points. (Construct the Table)
2. Using HPC Method, find the reduced level for all points. ( Construct the Table).
3. Show all required Arithmetic checks for your work. For Item 1 and 2.
4. What is the difference in height between points H and D?
5. What is the gradient of the line connecting A and J, knowing that horizontal distance = 200
m.
Answer:
pipe is old one with increased roughness
Explanation:
discharge is given as
V = 7.07 m/s
from bernou;ii's theorem we have
as we know pipe is horizontal and with constant velocity so we have
solving for friction factor f
f = 0.0324
fro galvanized iron pipe we have 
reynold number is
Re = 378750
from moody chart
therefore new friction factor is less than old friction factoer hence pipe is not new one
now for Re = 378750 and f = 0.0324
from moody chart
we have 
thus pipe is old one with increased roughness
