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3 years ago

Help pleasee I'm bad in this thing:(

Engineering

1 answer:

topjm [15]3 years ago

6 0

Answer:

f = 0.05Hz

Explanation:

Look at the graph. You can see that the wave complete one cycle in 20 seconds, so we can say that the period is 20s.

T = 20

frequency is just the inverse the period so

f = 1/T = 1/20 = 0.05Hz

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1. What did observations between 1912 and 1917 show?_____

valentinak56 [21]

The following set of prompts is astronomy related.

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5) It means that the universe has been growing or expanding ever since the Big Bang.

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7) In 1965, the American Radio Astronomers Arno Penzias and Robert Wilson inadvertently discovered Cosmic Microwave Background Radiation.

8) According to all recent observations and studies, the Universe has no center.

9) It is estimated the Universe is 13.8 Billion Years old.

10) According to the Big Bang Theory, the whole Universe existed within a bubble millions of times smaller than the size of a pinhead. It was hotter and denser than we could have imagined. Then it burst into flames. According to this belief, this explosion produced life as we know it. It should be highlighted that, while the hypothesis has been utilized to explain numerous scientific facts, it is still an unproven theory.

<h3>When did the study of astronomy begin?</h3>

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7 0

1 year ago

Find the mass if the force is 18 N and the acceleration is 2 m/s2

Nana76 [90]

Explanation:

f = ma

m = f/a

= 18N / 2m/s2

= 9kg

5 0

3 years ago

Read 2 more answers

The soil borrow material to be used to construct a highway embankment has a mass unit weight of 107.0 lb/cf and a water content

MrRissso [65]

Answer:

Option D

Explanation:

Given information

Bulk unit weight of 107.0 lb/cf

Water content of 7.3%,=0.073

Specific gravity of the soil solids is 2.62

Specifications

Dry unit weight is 113 lb/cf

Water content is 6%.

Volume of embankment is 440,000-cy

Borrow material

$Dry_{unit,weight}=\frac {bulk_{unit,weight}}{1+water_{content}}=\frac {107}{1+0.073}= 99.72041 lb/cf$

Embankment

Considering that the volume of embankment is inversely proportional to the dry unit weight

$\frac {V_{embankment}}{V_{borrow}}=\frac {Dry_{borrow}}{Dry_{embankment}}$

Therefore, $V_{borrow}=V_{embankment} *\frac {Dry_{embarkement}}{Dry_{borrow}}$

$V_{borrow}=440,000-cy*\frac {113 lb/cf }{99.72041 lb/cf }= 498594-cy$

Therefore, volume of borrow material is 498594-cy

(b)

The weight of water in embankment is found by multiplying the moisture content and dry unit weight.

Assuming that all the specifications are achieved, weight of water in embankment=0.06*113=6.78 lb/cf

Since $1 yd^{3}= 27 ft^{3}$

The embankment requires water of 6.78*27*440000= 80546400 lb

Borrow materials’ water will also be 0.073*99.72041=7.27959 lb/cf

Borrow material requires water of 7.27959*27*498594=97998120 lb

Extra water between borrow material and embankment=97998120 lb-80546400 lb=17451720 lb

$Unit_{weight}=\frac {17451720}{498594}=35.00186 lb$

1 gallon is approximately $8.35 yd^{3}$ hence

$\frac {35.00186 lb/yd^{3}}{8.35}=4.19184 gallons/yd^{3}$

That's approximately 4.2 gallons

7 0

3 years ago

A spring-loaded piston-cylinder contains 1 kg of carbon dioxide. This system is heated from 104 kPa and 25 °C to 1,068 kPa and 3

labwork [276]

Answer:

Q = -68.859 kJ

Explanation:

given details

mass $co_2 = 1 kg$

initial pressure P_1 = 104 kPa

Temperature T_1 = 25 Degree C = 25+ 273 K = 298 K

final pressure P_2 = 1068 kPa

Temperature T_2 = 311 Degree C = 311+ 273 K = 584 K

we know that

molecular mass of $co_2 = 44$

R = 8.314/44 = 0.189 kJ/kg K

c_v = 0.657 kJ/kgK

from ideal gas equation

PV =mRT

$V_1 = \frac{m RT_1}{P_1}$

$=\frac{1*0.189*298}{104}$

$V_1 = 0.5415 m3$

$V_2 = \frac{m RT_2}{P_2}$

$=\frac{1*0.189*584}{1068}$

$V_1 = 0.1033 m3$

WORK DONE

$W =P_{avg}*{V_2-V_1}$

w = 586*(0.1033 -0.514)

W =256.76 kJ

INTERNAL ENERGY IS

$\Delta U = m *c_v*{V_2-V_1}$

$\Delta U = 1*0.657*(584-298)$

$\Delta U =187.902 kJ$

HEAT TRANSFER

$Q = \Delta U +W$

= 187.902 +(-256.46)

Q = -68.859 kJ

7 0

3 years ago

How might an operations manager alter operations to meet customer demand? Name at least two ways.

Citrus2011 [14]

One way is manager changes itself and the other one is the same thing i think.

4 0

3 years ago