I NEED HELP PLEASE! :)

Mathematics

1 answer:

Andrej [43]4 years ago

5 0

Answer:

Perpendicular

Step-by-step explanation:

To tell if the lines are perpendicular/parallel, you must look at the slope, but in this case, you must first get y by itself, like so:

3x + 7y = 15

-3x - 3x

___________

7y = -3x + 15

Divide both sides by 7:

y = $\frac{-3}{7}x + \frac{15}{7}$

Now the other equation:

7x - 3y = 6

-7x -7x

_________

-3y = -7x + 6

Divide both sides by -3:

y = $\frac{7}{3} x - 2$

You can see that the lines are perpendicular because the slopes ( $\frac{-3}{7} x$ and $\frac{7}{3}$ ) are opposite reciprocals.

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Help me please :( i really need help

iris [78.8K]

Answer:

B)41.2

C)0.736

D)6.132

Step-by-step explanation:

B) 412/10=41.2

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hope this helps

6 0

3 years ago

Please explain what I am to do with this problem 1x= -1; x+5=4

alexandr1967 [171]

1x=-1
that means whererever you see x, you replace it with -1

x is a placeholder for an unknown number

so repolace it

-1+5=4
5-1=4
true

3 0

3 years ago

Find the probability of getting a 1, 4, or 5 when you roll a standard six-sided die. Give your answer as a simplified fraction.

aivan3 [116]

The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined: