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Brums [2.3K]
3 years ago
9

You collect pennies. you start with one penny and double the number of pennies you have each day for the next 27 days. how many

pennies will you have at the end of 27 days?
Mathematics
1 answer:
Rudik [331]3 years ago
7 0
Imagine, at the first day you have only one penny. Then tomorrow you have 2 pennies, next day you have 4 (2x2), next day you have 8 (4x2), next day you have 16 (8x2).... and so forth.

It looks like geometric sequence isn't it? (the ratio between the number of pennies that you have from the 2nd day and the 1st day is 2)

So, by using geometric sequence theorem we can total those pennies until day-27

S (total pennies at day-27) = (1)(2^27-1) / 2-1 = 2^26 pennies

So, you have 2^26 pennies.. a big number of pennies huh?=))


{The formula is: S = a( r^n-1) / r-1
Where:
a= the number of pennies that you've got at the 1st day
n= number of days you spent to collect those pennies)
r= the ratio of the number of pennies}
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You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a
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Answer:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967      

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

\bar X=573 represent the sample mean

\mu population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=36-1=35

The Confidence level is 0.90 or 90%, the significance would be \alpha=0.1 and \alpha/2 =0.05, and the critical value for this case would be t_{\alpha/2}=1.690

And replacing we got:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967    

And the 90% confidence interval would be between [566.8033 and 579.1967]

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3 years ago
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