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KatRina [158]
4 years ago
12

What is the value of the expression below? 3/8+(-4/5)+(-3/8)+5/4

Mathematics
2 answers:
Tamiku [17]4 years ago
7 0
Before I put in the actual expression, let's figure out which sign is which. A positive sign and a negative sign make a negative sign. This applies for the first two pairs of signs. That would make it :

\frac{3}{8} - \frac{4}{5} - \frac{3}{8} + \frac{5}{4}

First thing is first : let's subtract the first two fractions. \frac{3}{8} - \frac{4}{5}. We would have to find the common multiple between 8 and 5, and that would be 40. So we change them both to 40, and we do to the numerator what we do to the denominator. \frac{15}{40} - \frac{32}{40}. That makes \frac{-17}{40}. (Now we subtract this and the next fraction. Again, we find the common multiple. The common multiple is 40.)

\frac{-17}{40} - \frac{3}{8} turns into \frac{-17}{40} - \frac{15}{40}. (-17 - 15 is -32.)

\frac{-32}{40} + \frac{5}{4} : (use common multiple, it changes) \frac{-32}{40} + \frac{50}{40}.

(-32 + 50 is 18.) \frac{18}{40}.

Simplified : \frac{9}{20}

ANS. IN FRACTION FORM : \frac{9}{20}
ANS. IN DECIMAL FORM : 0.45
Crazy boy [7]4 years ago
4 0
It will help you!

=-17/40+-3/8+5/4

= -4/5+5/4

= 9/20 

And the answer is 9/20 or decimals (0.45)

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
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Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

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