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3 years ago

15

Help plis 17. Find the sum of (10x + 3) and (- 4x - 2).

2 answers:

lidiya [134]3 years ago

5 0

(6x+1) ........ hope it help

OLEGan [10]3 years ago

4 0

Answer:

6x + 1

Step-by-step explanation:

1. (10x + 3) + (-4x -2) --> sum means to add.

2. Combine like terms --> 10x - 4x = 6x; 3 - 2 = 1.

3. 6x + 1

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You need to paint a decorative garden ornament that is in the shape of pyramid with a square base that is 3 inches long and has

Tom [10]

Answer:

Step-by-step explanation:

You need to paint a decorative garden ornament that is in the shape of pyramid with a square base that is 3 inches long and has a slant height of 13 inches.

a. A smaller pyramid has linear dimensions that are 3/4 times that of the larger pyramid. Does the smaller pyramid require 3/4 times the amount of paint? Explain: Answer: Yes

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3 years ago

Simplify (2xy3)4. <br><br> it said i was wrong so here

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4 years ago

2. How many milliliters are in 1 pint?<br>A. 120<br>B. 240<br>C. 480<br>D. 960<br>

svet-max [94.6K]

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Step-by-step explanation:

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3 years ago

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

$\displaystyle a-b+c=1.....[eq\ 1]$

Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

6 0

3 years ago

Darko found the distance between points A(3,-4) and B(-1,3) his work is shown below

alex41 [277]

In this question , Darko have to find the distance between A(3,-4) and B (-1,3) .

He uses the correct formula, which is

$d = \sqrt{ (x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}$

And on substituting the values , we will get

$d = \sqrt{ (-1-3)^2 + (3- (-4))^2 }$

And in this line, Darko did the mistake .

4 0

3 years ago

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