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2 years ago

Find the volume of the shape

Mathematics

2 answers:

padilas [110]2 years ago

7 0

Answer:

452.16 units³

Step-by-step explanation:

Volume = $\pi$ r²h

Volume = 3.14 × 6 × 6 × 4

Volume = 452.16 units³

alisha [4.7K]2 years ago

4 0

Answer:

around 452.39

Step-by-step explanation:

1) the equation for it is

$\pi {r}^{2} h$

(pi × r^2 × h

2) you use this formula by plugging in the equation

r=6

h=4

3) after that you just plug it into a calculator ^_^

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Which of the following choices

Lapatulllka [165]

Answer:

Denote AH as height of triangle ABC, with H lies on BC.

Applying sine theorem:

AH/AC = sin 60

=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7

=> Area of triangle ABC is calculated by:

A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611

=> Option C is correct.

Hope this helps!

3 0

3 years ago

Express the complex number 6 in complex trigonometric form. [See Attachment for answer choices]

kvasek [131]

Its B
Bscous etheres bot away that the nymber sis would go that long

5 0

3 years ago

WILL GIVE BRAINLIEST!!! NO UNHELPFUL ANSWERS OR I WILL REPORT!!!

tatyana61 [14]

Answer:

Step-by-step explanation:

because it is

8 0

2 years ago

Read 2 more answers

Evaluate |5-15| A) -10 B) 10 C) 20 D) -20

Oksana_A [137]

Answer:

B) 10

Step-by-step explanation:

|5-15|

Do what is inside the absolute values signs

5-15

-10

|-10|

Absolute value means always positive so take the positive value of -10

7 0

3 years ago

Read 2 more answers

The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3

RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that $p = 0.1$

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243$

There is a 24.3% probability that one of the calculators will be defective.

3 0

3 years ago