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Lena [83]
3 years ago
6

Jenna has at most $80 to spend on clothes. She wants to buy a pair of jeans for$22 and spend the rest on t-shirts. Each t-shirt

costs $8. Whats the maximum number of shirts she can buy
Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

7 shirts

Step-by-step explanation:

You first have to subtract 22 from 80, since that's how much she already spent, 80-22=58. Now you have to do 58/8, but since 8 doesn't divide evenly into 58, you have to go with the closet multiple of 8 which would be 56. 7x8=56, so Jenna can buy a maximum number of 7 shirts.

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Blizzard [7]

Given equation :

2/3 y + 15 = 9.


We need to subtract 15 from both sides first.


<h3>2/3 y + 15-15 = 9 -15     <em>Subtraction property of equality.</em></h3>

Now, we need to simplify it.


We get


<h3>2/3 y  = - 6    <em> simplification </em></h3>

Now, we need to get rid 2/3 from left side.


On multiplying both sides by 3/2,


<h3>2/3 y * 3/2  = - 6  * 3/2  <em>Multiplication property of equality.</em></h3>

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<h3>y = -9    <em>simplification </em></h3>
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3 years ago
Finley’s pumpkin had a mass of 6.5 kilograms before he carved it. After carving it the pumpkin had a mass of 3.9 kilograms. What
katen-ka-za [31]
Hello.

The percent decrease in the mass of the pumpkin for this case will be given by:
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 After carving it, the pumpkin decreases a percent of 40% in the mass.

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There are five sales associates at Mid-Motors Ford. The five associates and the number of cars they sold last week are: Sales As
Levart [38]

Answer:

a) There are 10 different samples of size 2.

b) See the explanation section

c) See the explanation section

Step-by-step explanation:

a) We need to select a sample of size 2 from the given population of size 5. We use combination to get the number of difference sample.

\{ {{5} \atop {2}} \} = \frac{5!}{2!(5-2)!} \\= \frac{5!}{2!3!} \\= \frac{120}{2*6} \\= \frac{120}{12} \\=10

b) Possible sample of size 2:

Peter Hankish 8 Connie Stallter 6 Juan Lopez 4 Ted Barnes 10 Peggy Chu 6

  1. Peter Hankish and Connie Stallter ( Mean = (8 + 6)/2 = 14/2 = 7)
  2. Peter Hankish and Juan Lopez (Mean = (8 + 4)/2 = 12/2 = 6)
  3. Peter Hankish and Ted Barnes (Mean = (8 + 10)/2 = 18/2 = 9)
  4. Peter Hankish and Peggy Chu (Mean = (8 + 6)/2 = 14/2 = 7)
  5. Connie Stallter and Juan Lopez (Mean = (6 + 4)/2 = 10/2 = 5)
  6. Connie Stallter and Ted Barnes (Mean = (6 + 10)/2 = 16/2 = 8)
  7. Connie Stallter and PeggyChu (Mean = (6 + 6)/2 = 12/2 = 6)
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  9. Juan Lopez and Peggy Chu (Mean = (4 + 6)/2 = 10/2 = 5)
  10. Ted Barnes and Peggy Chu (Mean = (10 + 6)/2 = 16/2 = 8)

c) The mean of the population is:

mean = \frac{(8+6+4+10+6)}{5} \\= \frac{34}{5} \\= 6.8

Comparing the mean of the population and the sample; we can say that most of the 2-size sample have their mean higher than that of the population sample. And the variation with the mean is not much. Some sample have their mean greater than population mean, while some sample have their mean greater than the population mean.

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timurjin [86]

Answer:

Domain:  All real numbers

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Step-by-step explanation:

The graph of this stretches as far left, right, up and down as it pleases.  It is unbounded.

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