Answer:
too blurry pls send new pic
Step-by-step explanation:
Answer:
The correct option is;
Segment ED ≅ segment FD because segment EF is perpendicular to a radius of circle A
Step-by-step explanation:
All chords perpendicular to the radius of a circle are bisected by the radius of the circle
Given that DA can be extended to the circumference of circle A to form a radius of the circle A, and that DA is perpendicular to EF, therefore, DA bisects EF or EF is bisected into two equal parts by DA such that segment ED is congruent to segment FD
Therefore, the correct option is that segment ED ≅ segment FD because segment EF is perpendicular to a radius of circle A.
For
to be continuous at
, we need to have
Note that
means that
, but that
is *approaching* 5. We're told that for
, we have
We can write
and the limit would be
and so
is discontinuous.
It's highest degree is 3, and has 3 terms, so this is a third-degree trinomial
