Question

If A is the center of the circle, then which statement explains how segment ED is related to segment FD? Circle A with inscribed triangle EFG; point D is on segment EF, point H is on segment GF, segments DA and HA are congruent, and angles EDA and GHA are right angles. segment ED ≅ segment FD because segment EF is perpendicular to a radius of circle A. segment ED ≅ segment FD because arc EF ≅ arc GF. segment ED ≅ segment FD because the inscribed angles that create the segments are congruent. segment ED ≅ segment FD because the tangents that create the segment EF share a common endpoint.

Answer 1

Answer:

The correct option is;

Segment ED ≅ segment FD because segment EF is perpendicular to a radius of circle A

Step-by-step explanation:

All chords perpendicular to the radius of a circle are bisected by the radius of the circle

Given that DA can be extended to the circumference of circle A to form a radius of the circle A, and that DA is perpendicular to EF, therefore, DA bisects EF or EF is bisected into two equal parts by DA such that segment ED is congruent to segment FD

Therefore, the correct option is that segment ED ≅ segment FD because segment EF is perpendicular to a radius of circle A.