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2 years ago

PLEASEE HELPP MEEE WITH NUMBERSSS 9 AND 10

Mathematics

1 answer:

insens350 [35]2 years ago

5 0

Answer:

hi dont report me we are friends can i get brainliest plzz?

Step-by-step explanation:

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3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0

Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

$\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0$

Hence, Proved that $\sf \frac{3}{m+4} - \frac{4}{m} = 6$ is equivalent to $\sf 6m^2+25m+16 = 0$ .

6 0

2 years ago

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Erin received the following scores on her last four spelling tests.

Tatiana [17]

The second one, 82% is Erin's highest score

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2 years ago

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Please help me I don’t understand anything about this

Alik [6]

Answer:

Step-by-step explanation:

It can be crossed if sides are same in multiply, as shown in the answer

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2 years ago

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Pls help will give brainly (again)

Elan Coil [88]

Answer:

Step-by-step explanation:

First, simplify the exponents:

2*(3^6*3*-5)

2*((3*3*3*3*3*3)*(1/3*3*3*3*3))

2*(729*0.00411522633)

Then solve from there:

2*2.99999999457

5.99999998914

Since there is only whole numbers and a fraction present, im assuming you have to round:

5.99999998914

6 is your answer

Hope this helps!

7 0

2 years ago

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

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2 years ago

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