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Phoenix [80]
3 years ago
9

Find m∠YOZ in the figure if m∠XOZ = 86°.

Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>7</em><em> </em><em>degree</em><em>.</em>

<em>pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>

<em>h</em><em>ope</em><em> it</em><em> helps</em>

svet-max [94.6K]3 years ago
3 0
The answer is 7 degrees
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A snack bar sells two sizes of drinks. A large drink is $5 and a small drink is $3. In one day, they sold 60 drinks for a total
pshichka [43]

Answer:

Step-by-step explanation:

Given:

Cost of L = $5

Cost of S = $3

No. of drinks sold = 60 drinks

Total sale = $220

Solution:

L + S = 60 - (1) (multiplying by 3)

5L + 3S = 220 - (2)

(-)3L +(-) 3S = (-)180 - (1)

2L = 40

L = 40 / 2

L = 20 Large drinks

20 + S = 60

S = 60 - 20

S = 40 small drinks

Therefore, 20 large drinks and 40 small drinks

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7 0
3 years ago
Read 2 more answers
Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = –3x2 – 36x – 60?
Zanzabum

Answer:

I think it is D.

Step-by-step explanation:

5 0
2 years ago
Based on Charles Waddell Chestnutt's "The Wife Of His Yout. Which of the following statements about Mr. Ryder is true? Choose al
Serjik [45]
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3 0
2 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, \overline x _1 = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, \overline x _2 = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

\left (\bar{x}_{2}- \bar{x}_{1}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

t_{(0.025, \, 18)} = 1.734

C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}

t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0
2 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
mariarad [96]
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5 0
3 years ago
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