Answer:
prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S
Explanation:
Given that S = { p q |p, q are prime numbers greater than 0}
E = {0, −2, 2, −4, 4, −6, 6, · · · }
To prove by constructing a bijection from S to E
detailed solution attached below
After the bijection :
<em>prove that | S | = | E |</em> : every element of S there is an Image on E , while not every element on E has an image on S
∴ we can say sets E and S are infinite sets
Answer Explanation : The general principles for design for assembly (DFA) are,
- MINIMIZE NUMBER OF COMPONENT
- USE STANDARD COMMERCIALLY AVAILABLE COMPONENTS
- USE COMMON PARTS ACROSS PRODUCT LINES
- DESIGN FOR EASE OF PART FABRICATION
- DESIGN PARTS WITH TOLERANCE THAT ARE WITHIN PROCESS CAPABILITY
- MINIMIZE USE OF FLEXIBLE COMPONENT
- DESIGN FOR EASE OF ASSEMBLY
- USE MODULAR DESIGN
- REDUCE ADJUSTMENT REQUIRED
STEPS TO MINIMIZE THE NUMBER OF PARTS
- USE OF INCORPORATE HINGS
- USE OF INTEGRAL SPRINGS
- USE OF SNAP FITS
- USE OF GUIDES BEARINGS
- USE OF COVERS
Answer:
00100111
Explanation:
Given;
10010110
10010000
Add these like normal binary numbers
10010110
10010000
-------------
(1)00100110
-------------
ignore extra (1) on left since it's a carry.
Add 1 to the above result to make it a 1's complement result
00100110 + 1 = 00100111
Answer: 00100111
Explanation:
Use trigonometry. The horizontal force is:
Fₓ = F cos θ
Fₓ = 20 N cos 60°
Fₓ = 10 N
