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Answer:
Engineering drawing abbreviations and symbols are used to communicate and detail the characteristics of an engineering drawing.
There are many abbreviations common to the vocabulary of people who work with engineering drawings in the manufacture and inspection of parts and assemblies.
Technical standards exist to provide glossaries of abbreviations, acronyms, and symbols that may be found on engineering drawings. Many corporations have such standards, which define some terms and symbols specific to them; on the national and international level, like BS8110 or Eurocode 2 as an example.
Explanation:
Answer:
The maximum acceleration experienced by the sprinter is and it is experienced in the first phase when the sprinter starts his sprint.
Explanation:
Since the sprinter attains a final speed of 34 km/h in runing 200 meters while starting from rest we have
Using the third equation of kinematics we have
where
v is the final speed
u is the initial speed
a is the acceleration
s is the distance covered
Since it is given that sprinter starts from rest thus u= 0 m/s and v= 34 km/h = 9.4m/s this speed is attained at s = 78 m
Applying values in the above equation we get
Since after that the sprinter moves at a constant velocity thus in that phase it's acceleration is
Now since the sprinter decelerates to 30 km/h or 8.33 m/s in final 63 meters thus the deceleration experienced is again found by third equation of kinematics as
Upon comparing the maximum acceleration experienced by the sprinter is
Answer:
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Answer:
36π inches ≈ 113.0973 inches
Explanation:
The circumference of the wheel is pi times its diameter.
C = πd
C = π(36 in) = 36π in ≈ 113.0973 in
The distance around the wheel is 36π inches, about 113.0973 inches.