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3 years ago

Part B Does the size of the particles change as the substance changes state?

1 answer:

8 0

The particles themselves do not change in size. When changing state the distance between the particles is what changes due to overcoming the intermolecular forces between the particles.

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A point charge with charge q1 = 3.40 μC is held stationary at the origin. A second point charge with charge q2 = -4.90 μC moves

expeople1 [14]

Answer:

-0.79 J

Explanation:

We are given that

$q_1=3.4\mu C=3.4\times 10^{-6} C$

$1\mu C=10^{-6} C$

$q_2=-4.9\mu C=-4.9\times 10^{-6} C$

$x_1=0.125,y_1=0$

$x_2=0.280,y_2=0.235$

We have to find the work done by the electric force on the moving point charge.

$r_1=\sqrt{x^2_1+y^2_1}=\sqrt{(0.125)^2+0}=0.125$

$r_2=\sqrt{(0.280)^2+(0.235)^2}=0.366$

Work done, $W=kq_1q_2(\frac{1}{r_1}-\frac{1}{r_2})$

Where $k=9\times 10^9$

Using the formula

$W=9\times 10^9\times 3.4\times 10^{-6}\times(-4.9\times 10^{-6})(\frac{1}{0.125}-\frac{1}{0.366})$

$W=-0.79 J$

5 0

3 years ago

A skateboarder is accelerating forward. How would his acceleration change if he had more mass?

exis [7]

Answer:

If the force remains the same, the acceleration would decrease

Explanation:

According to Newton's second law, the acceleration of an object is given by

$a=\frac{F}{m}$

where

F is the force applied to the object

m is the mass of the object

As we see from the formula, the acceleration a is inversely proportional to the mass, m. Therefore, if the force F remains constant, this means that if the mass of the skateboarder increases, then the acceleration will decrease.

4 0

3 years ago

What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?

Marysya12 [62]

The velocity is 3.75

5 0

3 years ago

Sodium chloride and calcium carbonate combine to form sodium carbonate and calcium chloride in the reversible reaction.

lidiya [134]

Answer:

I think is Number 2

The rate at which calcium chloride is equal to the rate at which sodium chloride is produced.

Let me know if I'm wrong.

6 0

2 years ago

Read 2 more answers

The blades of a fan running at low speed turn at 250 rpm. When the fan is switched to high speed, the rotation rate increases un

fgiga [73]

Answer:

1.82 rad/s².

Explanation:

Applying,

α = (ω₂-ω₁)/t..................... Equation 1

Where α = angular acceleration of the fan blades, ω₂ = final angular velocity of the fan blades, ω₁ = initial angular velocity of the fan blades, t = time.

Given: ω₂ = 350 rpm = (350×0.1047) rad/s = 36.645 rad/s. ω₁ = 250 rpm = (250×0.1047) rad/s = 26.175 rad/s, t = 5.75 s.

Substitute into equation 1

α = (36.645-26.175)/5.75

α = 10.47/5.75

α = 1.82 rad/s².

Hence the magnitude of the angular acceleration of the fan blades = 1.82 rad/s²

8 0

3 years ago