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Harrizon [31]
3 years ago
8

The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.

Physics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

10.7*10^{6}

Explanation:

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Circuit diagram showing three resistors in series with an ammeter,a cell and a switch​
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the mayflower

Explanation:

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3 years ago
A box of mass m1 rests on a smooth, horizontal floor next to a box of mass m2. Suppose the force of 20.0 N pushes on two boxes o
meriva

Answer:

Explanation:

Given

acceleration of system a =1.2 m/s^2

Normal Force N=4.45 N

Force exerted F=20 N

Thus

F=(m_1+m_2)a

\frac{20}{1.2}=m_1+m_2

16.67=m_1+m_2-------1

Normal reaction N=m_2a

4.45=m_2\times 1.2

m_2=3.70 kg

therefore m_1=16.67-3.70

m_1=12.96 kg

8 0
3 years ago
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Suppose you average 75 MPH over the first halfof a drive, and your average speed for the entiredrive is 60 MPH. What was your av
alexandr402 [8]

Answer:

x = 45 MPH

Explanation:

given,

Average speed of the first half = 75 MPH

Average speed of entire ride = 60 MPH

Average speed of the second half = ?

let the average speed of the second half = x MPH

now,

average of entire ride is given as 60 mph so,

 \dfrac{75+x}{2} = 60

 75+x= 2\times 60

       75 + x = 120

         x = 120 -75

        x = 45 MPH

hence, the average speed of the second half comes out to be 45 MPH.

5 0
3 years ago
A white billiard ball with mass mw = 1.37 kg is moving directly to the right with a speed of v = 3.14 m/s and collides elastical
Ira Lisetskai [31]

That latest value for the Angle is in Grads, not in Kilograms.

Apply law of conservation of momentum along vertical direction.

m_1v_1sin\theta_1-m_2v_2sin\theta_2=0

v_2=\frac{v_1sin\theta_1}{sin\theta_2}=\frac{sin54}{sin36}v_1 = 1.376v_1

Apply law of conservation of momentum along the horizontal direction

m_1u_1=m_1v_1cos\theta_1+m_2v_2cos\theta_2

u_1=v_1(cos\theta_1+1.376cos\theta_2)

u_1=v_1(cos(54)+1.376cos(36))

u_1=(1.7) v_1

v_1= \frac{3.14}{1.7}=1.84m/s

The second ball velocity is v_2 = (1.376)(1.84)=2.531m/s

The magnitud of final total momentum is

m(v_1+v_2)=(1.37)(2.531+1.84)=5.98kgm/s

The magnitude of final energy is

\frac{1}{2}m(v^2_1+v^2_2)=\frac{1}{2}(1.37)(2.531^2+1.84^2)=6.07J

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3 years ago
A blank star has a greater temperature than a blank star
zheka24 [161]

Blue is greater than Red

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3 years ago
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