The wavelength is related to the frequency by the relationship:
where v is the wave speed and f is its frequency.
The speed of sound in air is v=344 m/s. The lowest frequency is f=20.0 Hz, so the corresponding wavelength is
The highest frequency is
, so the corresponding wavelength is
Therefore, the range of wavelengths of audible sound in air is
[0.017 m - 17.2 m]
Answer:
0.233
Explanation:
Given that
Diameter of rotor, d = 40 m
Power of rotor, P = 90 kW
Speed of the wind, v = 8 m/s
Density of air, p = 1.2 kg/m³
It is a known fact that
KE = ½mv², where mass flow rate, m
m = p.A.v, where Area, A
A = πd²/4
A = (3.142 * 40²)/4
A = 3.142 * 1600/4
A = 3.142 * 400
A = 1256.8 m², substitute for A in the mass flow rate equation
m = p.A.v
m = 1.2 * 1256.8 * 8
m = 12065.28, substitute for m in the KE equation
KE = ½mv²
KE = ½ * 12065.28 * 8²
KE = 12065.28 * 32
KE = 386088.96 W or
KE = 386.1 kW
Fraction of kinetic energy converted to electric energy is
Fraction = Electric Power / Total KE
Fraction = 90 / 386.1
Fraction = 0.233
Answer:
physical quantity that only has magnitude and no other characteristics.
Explanation:
so no velocity only magnitude
The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen.
Answer:0.077
Explanation:
Given
banked designed for traffic moving at 
Radius of the curve 201 m
Actual traffic velocity =
For banking of road
Centripetal acceleration is given by
Taking component of centripetal acceleration
along and perpendicular to surface
From FBD
----1
where 
is frictional force
----2
and we know coefficient of friction is given by
