Answer:
The answer to your question is a) C = 0.056 cal/g°C b) 107.8 g/mol
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The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:
There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:
The mass of Ni to be deposited is 1.22 grams. The charge required is given as:
The current required to transfer 4010.7 C of charge in 1800 seconds is given as:
Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
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