Answer: In factories they burn coal under a giant container(a really big gumbo pot pretty much). when the fire is hot enough it starts to boil. When it boils it creates steam and the steam blows on a fan that makes electricity.
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
is a combustion reaction
Explanation:
In a combustion reaction a chemical substance (usually organic substances) are reacted with oxygen to form the most stable oxides and heat.
CH₄ + 2 O₂ → CO₂ + 2 H₂O
In a double displacement reaction two compounds exchange elements.
AB + CD → AC + BD
In a decomposition reaction a compound is split into simpler substances.
AB → A + B
In a synthesis reaction two elements are combined to form another compound. A + B → AB
In a single displacement reaction a compound exchange one of its elements.
AB + C → AC + B
Learn more about:
types of chemical reactions
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Acute: Can be repaired by the body using white blood cells.
Chronic: High doses causing internal bleeding and breakdown of cells causing slow death, 90% of the times cannot be fixed by any medicines.
The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
= 0.055 moles of NaH2PO4 which is also equal to the number of moles of H2PO4.
[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
= 0.055/ ( 355 ×10^-3)
= 0.155 M
Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)
1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
= 0.0563 moles
[HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
= 0.0563/(355×10^-3)
= 0.1586 M
Both H2PO4^2- and HPO4^2- are weak acids the undergoes partial dissociation
Ka of H2PO4- = 6.20 × 10^-8
[H+] =Ka*([H2PO4-]/[HPO4(2-)]
= (6.20 ×10^-8)×(0.155/0.1586)
= 6.059 ×10^-8 M
pH = - log[H+]
= - log (6.059×10^-8)
= 7.218
Polar protic solvents actually speed up the rate of the unimolecular substitution reaction because the large dipole moment of the solvent helps to stabilize the transition state. The highly positive and highly negative parts interact with the substrate to lower the energy of the transition state.
