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Mazyrski [523]
3 years ago
15

A basketball weighs approximately 1.35 kg. What is this mass in grams (g)? step by step

Chemistry
1 answer:
umka21 [38]3 years ago
5 0

Answer:

1350 g

Explanation: just add a 0

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The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release
KATRIN_1 [288]

The mass of melted gold to release the energy would be  3, 688. 8 Kg

<h3>How to determine the mass</h3>

The formula for quantity of energy is given thus;

Q = n × HF

Where n represents number of moles

HF  represents  heat of fusion

To find the number of moles, we have

235.0 = n × 12.550

number of moles = \frac{235}{12. 550} = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Let's note that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be  3, 688. 8 Kg

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2 years ago
Effect of Two-Step Homogenization on the Evolution of Al3Zr Dispersoids in Al-0.3Mg-0.4Si-0.2Zr Alloy
AlekseyPX

Effect of Two-Step Homogenization on the Evolution of Al3Zr Dispersoids in Al-0.3Mg-0.4Si-0.2Zr Alloy Al3Zr nano-particles can be introduced in Al-Mg-Si 6xxx alloys to improve their elevated temperature behavior and recrystallization resistance. The effect of two-step homogenization treatments on

the precipitation of Al3Zr dispersoids in Al-0.3Mg-0.4Si-0.2Zr alloy was investigated and compared to

<h3>What is Homogenization?</h3>

Any of a number of methods, including homogenization and homogenisation, are used to uniformly combine two liquids that are insoluble in one another. To do this, one of the liquids is changed into a state in which very minute particles are evenly dispersed across the other liquid. The process of homogenizing milk, in which the milk fat globules are equally distributed throughout the remaining milk and reduced in size, is a classic example. In order to create an emulsion, two immiscible liquids (i.e., liquids that are not soluble in all amounts one in another) must be homogenized (from "homogeneous"; Greek, homos, same + genos, kind)[2] (Mixture of two or more liquids that are generally immiscible).

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7 0
1 year ago
A cube of plastic 1.2x10^-5 km on a side has a mass of 1.1 g. what is its density in g/cm^3
Vesna [10]
Length of 1 side 1.2*10^-5km =1.2*10^-5*10^5 =1.2cm 

<span>volume of the cube (1.2)^3=1.728 cm^3 </span>

<span>density= mass/volume= 1.1/1.728=0.636 g/cm^3</span>
7 0
3 years ago
Read 2 more answers
The strength of an acid is affected by the polarity of the bond connected to the acidic hydrogen. The more highly polarized this
alexgriva [62]

Answer:

Explanation:

Oxyacids are acid containing oxygen; they are also known as acid-alcohol or acid-phenol. As said earlier, the strength of these acids increases with increases in the polarity of these compounds. So, what makes the polarity is as a result of the electronegative substituents attached to it. Halogen family possesses the highest electronegativity in the periodic table, and electronegativity decreases down the group.

The ranking of the oxyacids in order of decreasing acid strength from strongest to weakest acid is:

HClO3 > . HClO2 > HClO > HBrO

5 0
3 years ago
In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.
DaniilM [7]

Answer:

0.2 M.

Explanation:

  • For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

  • For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

  • For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

5 0
3 years ago
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