Answer:
Mass = 157.5 g
Explanation:
Given data:
Mass of CO needed = ?
Mass of Fe formed = 209.7 g
Solution:
Chemical equation:
3CO + F₂O₃ → 2Fe + 3CO₂
Number of moles of Fe:
Number of moles = mass/ molar mass
Number of moles = 209.7 g/ 55.85 g/mol
Number of moles = 3.75 mol
Now we will compare the moles of iron and carbon monoxide.
Fe : CO
2 : 3
3.75 ; 3/2×3.75 = 5.625 mol
Mass of CO:
Mass = number of moles × molar mass
Mass = 5.625 mol × 28 g/mol
Mass = 157.5 g
<span>CH4 + 4 Cl2 → CCl4 + 4 HCl
(4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4
(4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl
CCl4 + 2 HF → CCl2F2 + 2 HCl
(2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl
11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>
Answer:
no no no who are these some look good but are black what is this
<span>d. A catalyst will be used up in the reaction is wrong,
amount of catalyst should not change</span>
<span>The concentration of pb2+ = 1.00mg/ml
Diluted Solution is 6.0 x 102 ml = 612 ml
Volume of the concentration of pb2+ is 0.054 mg/l is v
(vL)(1.00mg/ml) = (.612L)(0.054mg/l)
Volume = 0.033048L
Volume of the concentration of pb2+ is 0.054 mg/l = 33.048 ml.</span>
