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Semmy [17]
3 years ago
6

An angle measures 47.2° less than the measure of its supplementary angle. What is the measure of each angle? on ixl

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:

The measure of one angle is 113.6^o, and the measure of the other one is 66.4^o

Step-by-step explanation:

Recall that supplementary angles are those whose addition renders 180^o

We need to find the measure of two such angles whose difference is precisely 47.2^o.

Let's call such angles x and y, and consider that angle x is larger than angle y, so we can setup the following system of equations:

x+y=180^o\\x-y=47.2^o

We can now solve this by simply combining term by term both equations, thus  cancelling the term in "y", and solving first for "x":

x+y=180^o\\x-y=47.2^o\\\\2x=180^o+47.2^o\\2x=227.2^o\\x=113.6^o

So, now we have the answer for one of the angles (x), and can use either equation from the system to find the measure of angle "y":

y=180^o-x\\y=180^o-113.6^o\\y=66.4^o

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Step-by-step explanation:

6 0
2 years ago
HELP!! Given f(x)=5x squared and g(x) = x squared + 2x squared - 5x, what is F (x) * g(x)?
TEA [102]
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Pull the factors out

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3 years ago
What is 5 raised to the 5th power?
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8 0
3 years ago
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Amanda teaches all of the bass and viola students. All of her classes have the same number of students. Each class has the great
alexandr402 [8]

Answer:

5 classes - 2 bass classes and 3 viola classes.

Step-by-step explanation:

Find the greatest common factor (GCF)

List the factors of 20 and 30:

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30: 1, 2, 3, 5, 6, 10, 15, 30

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hope this helps! <3

6 0
1 year ago
Please help me solve for x
kkurt [141]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The shown pair of angles are Co interior angle pair, therefore the sum of those angles is 180°

\qquad \sf  \dashrightarrow \: 130 \degree + 7x + 1 \degree = 180 \degree

\qquad \sf  \dashrightarrow \: 131 \degree + 7x = 180 \degree

\qquad \sf  \dashrightarrow \:  7x= 180 \degree - 131 \degree

\qquad \sf  \dashrightarrow \:  7x= 49 \degree

\qquad \sf  \dashrightarrow \:  x=49 \degree \div 7

\qquad \sf  \dashrightarrow \:  x=7 \degree

The required value of x is 7°

3 0
2 years ago
Read 2 more answers
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