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2 years ago

15

I got the answer D is this correct? will vote brainliest

1 answer:

Marina86 [1]2 years ago

4 0

Answer:

yes its a correct answer hope it will help u.......

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Can someone plss answer the Circled question for the dot plot :)))))

frutty [35]

4 has the most. Sorry if it’s wrong, good day to you

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3 years ago

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How do you find endpoints of a line segment with a given endpoint and midpoint?

seraphim [82]

In order to find the second endpoint or a line segment given the first and the midpoint, you need to realize that the midpoint is an average of the two endpoints. Given that fact, we can derive this formula looking at x values of points A and B with midpoint M. Remember this is only looking at the x values.

(A + B)/2 = M

So if we are looking for A, we can solve for A and use this modified formula.

(A + B)/2 = M

A + B = 2M

A = 2M - B

Now we can do this with the y values of these points as well. We then have the coordinates of both parts of A.

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2 years ago

Whats the answer?please tell me!!

zavuch27 [327]

95.72 + 5.228 = 100.948

6 0

3 years ago

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Consider the tangent line to the curve y = 6 sin(x) at the point (π/6, 3). (a) Find a unit vector that is parallel to the tangen

mojhsa [17]

Answer:

$y=\frac{\pi }{6}+5.196(x-3)$

Step-by-step explanation:

We have given the equation y = 6 sin (x)

On differentiating both side $\frac{dy}{dx}=m=6cosx$

As it passes through the point $(\frac{\pi }{6},3)$

So $\frac{dy}{dx}=6cos\frac{\pi }{6}=5.196$

Now the unit vector is parallel to the tangent so m will be 5.196

This passes through the point $(\frac{\pi }{6},3)$

So unit vector will be $y-\frac{\pi }{6}=5.196(x-3)$

$y=\frac{\pi }{6}+5.196(x-3)$

5 0

3 years ago

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

Lorico [155]

Answer:

$(7,\frac{13}{3})$

Step-by-step explanation:

we have

<em>The equation of the first line</em>

$y=\frac{1}{3}x+2$ ------> equation A

<em>The equation of the second line</em>

$y=\frac{4}{3}x-5$ ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

$(-4)y=(-4)(\frac{1}{3}x+2)$

$-4y=-\frac{4}{3}x-8$ --------> equation C

Adds equation B and equation C

$y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}$

<em>Find the value of x</em>

substitute the value of y

$\frac{13}{3}=\frac{1}{3}x+2$

$\frac{1}{3}x=\frac{13}{3}-2$

Multiply by 3 both sides

$x=13-6$

$x=7$

therefore

The solution to the system of equations is the point $(7,\frac{13}{3})$

5 0

3 years ago

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