Answer:
44
Step-by-step explanation:
Answer:
Y~x
Y = k × v
Y = 22
Step-by-step explanation:
Y~ x
Y = k × X
Since the question isn't complete,we are going to assign figures to complete this very question and move on to other things and you can as well solve questions that are similar to this ones.
Now let's assume that the question says that is 6 when x is 3,what is y when x is 11.
To solve this question above,we need to find the constant of variation which will then enable us to know what y is when x is 11
Y~ x
Y = k × V
When y is 6 and x is 3,k will be
6 = 3k
K= 2
Now when k is 2,x is 11,y Will then be
Y = kx
Y = 2 × 11
Y = 22.
With this procedure,one can find any value of x or y when they have the constant of variation.
If you have a figure assigned to x and y is to be found,the constant of variation will help to get y and vice versa
Answer:
Step-by-step explanation:
here
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
