Answer:
A. 7,348
Step-by-step explanation:
P = le^kt
intitial population = 500
time = 4 hrs
end population = 3,000
So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.
A = Pe^rt
3,000 = 500e^r4
now we can solve for r
divide both sides by 500
6 = e^r4
now because the variable is in the exponent, we have to use a log
ln(6) = 4r
we can plug the log into a calculator to get
1.79 = 4r
divide both sides by 4
r = .448
now lets plug it back in
A = 500e^(.448)(6 hrs)
A = 7351.12
This is closest to answer A. 7,348
Hi there!
So let's see, we have a die and need to know the probability of rolling a number less than or equal to 4. Let's list the numbers that are less than or equal to 4: 1, 2, 3, 4. Now, since we know that there are 6 numbers on a die and 4 of them are less than or equal to 4, we can set up a fraction to find the percentage. The fraction would be 4/6 because 4 out of the 6 numbers on the die are less than or equal to 6. We can simplify 4/6 to 2/3 as well. To find the percentage, all we need to do is divide the numerator by the denominator. This leaves us with approximately 66.66%.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
negative, it'll be negative 2
Hello There!
To find the mean, add up all the numbers and divide according to how many numbers there are. The mean for this set would be <em>"9"</em>
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To find the median, place the numbers in value order and find the middle. if there is no middle, add up the two numbers in middle and divide by 2. In this set, the median would be <em>"8.5"</em>
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To find the mode or modal value, it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode. In this set, there would be no mode.
The range of a set of data is the difference between the highest and lowest values in the set. In this set, the range would be <em>"12"</em>
