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insens350 [35]
3 years ago
10

6. As you go down a family or group on the periodic table *

Chemistry
2 answers:
maks197457 [2]3 years ago
4 0

Answer:

the atoms have more valence electrons

Explanation:

icang [17]3 years ago
4 0
Idnshansbdnsjsjsjsjs
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Which of the following is the BEST description of a budget? *<br> 10
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A budget is an estimation of revenue and expenses over a specified future period of time and is usually compiled and re-evaluated on a periodic basis. Budgets can be made for a person, a group of people, a business, a government, or just about anything else that makes and spends money.

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a solid sample of oil is warmed until it turns into a liquid. which property of the oil will decrease?
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  I think the answer is it turnes into a gas. Hope it helps! :) Asnwer is density.

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3 years ago
What is the net ionic charge of a nitrogen ion? <br> +3 <br> -1 <br> -2 <br> -3
IgorLugansk [536]
-3 is the answer your looking for
8 0
3 years ago
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NEED HELP ASAP!!! What is the density of each of the following gases at STP? Show your work.
BaLLatris [955]

Answer:

A. 1.63g/dm^3 (3 s.f.)

B. 0.833g/dm^3 (3 s.f.)

C. 1.92g/dm^3 (3 s.f.)

Explanation:

Please see attached picture for full solution.

3 0
3 years ago
When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed
gizmo_the_mogwai [7]

Answer:

             66 g of CO₂

Solution:

The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
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