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Maslowich
3 years ago
14

Which feature is most likely found at a divergent boundary?

Chemistry
2 answers:
bogdanovich [222]3 years ago
8 0

Fault-block mountain

I know because I just took the quiz, and it said the correct answer at the end.

kkurt [141]3 years ago
7 0

Answer:

Fault-block mountain

In geography, fault-block mountains arise when the Earth's crust pulls apart and divides. Some parts of the Earth are pushed upwards whereas the other moves downward forming a divergent boundary. In geological studies, a divergent boundary can be described as a linear feature which arises due to plate tectonics which are being pulled apart from each other. Hence, fault-block mountains are most likely to be seen in a divergent boundary.

Most active divergent plate boundaries occur between oceanic plates and exist as mid-oceanic ridges. Divergent boundaries also form volcanic islands, which occur when the plates move apart to produce gaps that molten lava rises to fill.

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Which state of matter would be described as having highly energized, charged particles that move extremely fast
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Plasma:
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Composition:
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Result:
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8 0
3 years ago
What all indicates a CHEMICAL change? *
myrzilka [38]

one substance becomes two new substances

6 0
3 years ago
An acid, like HCI, would...
frosja888 [35]

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Explanation:

6 0
3 years ago
Read 2 more answers
Find the ph of a buffer that consists of 0.18 m ch3nh2 and 0.73 m ch3nh3cl (pkb of ch3nh2 = 3.35)?
ozzi
Hello!

First, we need to determine the pKa of the base. It can be found applying the following equation:

pKa=14-pKb=14-3,35=10,65

Now, we can apply the Henderson-Hasselbach's equation in the following way:

pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04

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8 0
3 years ago
What volume will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C?
wlad13 [49]

Answer:

V = 27.98 L

Explanation:

Given data:

Mass of CO₂ = 33.0 g

Pressure = 500 torr

Temperature = 27°C

Volume occupied = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 33.0 g/ 44 g/mol

Number of moles = 0.75 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K  

Now we will convert the temperature.

27+273 = 300 K

Pressure = 500 /760 = 0.66 atm

By putting values,

0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K  × 300 K

V = 18.47 atm.L/0.66 atm

V = 27.98 L

4 0
3 years ago
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