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3 years ago

Why do scientists look for patterns in the world?

Chemistry

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

B. Patterns can help explain observations.

Explanation:

Hope this helps

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811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of

Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

Provided heat (Q): 811.68 J

Mass of the metal (m): 95 g

Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0

3 years ago

Pls Help me I am stuck on this question.

kolbaska11 [484]

Answer:

compound is the answer

4 0

3 years ago

The diagram below shows a longitudinal wave at one instant in its motion. Each oval represents a particle acted on by the ener t

Anton [14]

Answer:

the first line

Explanation:

A rarefaction is a region in a longitudinal wave where the particles are furthest apart. ... The region where the medium is compressed is known as a compression and the region where the medium is spread out is known as a rarefaction.

use this picture as a reference:

8 0

3 years ago

Read 2 more answers

Please help ————//-//

grandymaker [24]

Probably b because soil can’t be the exact same and so that cancels out a and d

6 0

3 years ago

Read 2 more answers

What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?

lions [1.4K]

Answer:

$m=33.9g$

Explanation:

Hello,

In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

$Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J$

Afterwards, the mass of ice that can be melted is computed by:

$Q=n \Delta _{fus}H$

So we solve for moles with the proper units handling:

$n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol$

Finally, with the molar mass of water we compute the mass:

$m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g$

Best regards.

7 0

3 years ago