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3 years ago

According to one acid base theory a base is an 1, h2 acceptor 2, h2 donor 3, h+ acceptor 4,h+ donor

Chemistry

1 answer:

kolbaska11 [484]3 years ago

5 0

Answer:

3, H⁺ acceptor

Explanation:

Let's consider Bronsted-Lowry acid-base theory.

According to this theory, an acid is a substance that donates H⁺ ions. For example, HCl is an acid.

HCl + H₂O = Cl⁻ + H₃O⁺

Cl⁻ is the conjugate base of HCl.

According to this theory, a base is a substance that accepts H⁺ ions. For example, NH₃ is a base.

NH₃ + H₂O = NH₄⁺ + OH⁻

NH₄⁺ is the conjugate acid of NH₃.

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An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t

topjm [15]

Answer:

$\boxed{3}$

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

$\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )$

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

$\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}$

Data:

$n_{f} = 2$

λ = 657 nm

Calculation:

$\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}$

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3 years ago

Using your knowledge of symbols, determine which compound listed must contain both copper and oxygen.

Colt1911 [192]

Answer:

Malachite

Explanation:

Malachite is the only listed compound that must contain copper and oxygen.

Copper and oxygen are both elements found on the periodic table. They have the following symbols;

Copper = Cu

Oxygen = O

From the given choices, only option 1 has the symbol Cu and O.

So only malachite contains both copper and oxygen.

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2 years ago

28. Describe the molecular geometry and hybridization of the N, P, or S atoms in each of the following compounds. (a) H3PO4, pho

Whitepunk [10]

Answer:

See explanation

Explanation:

The molecular geometry of an atom is connected to the number of electron pairs that surround it(whether lone pairs or bonding pairs) as well as its hybridization state. We shall now examine the N, P, or S atoms in each of the following compounds.

In H3PO4, P has a tetrahedral molecular geometry and is sp3 hybridized.

b) In NH4NO3

N is sp3 hybridized in NH4^+ and sp2 hybridized in NO3^-. Also, N is tetrahedral in NH4^+ but trigonal planar in NO3^-.

c) In S2Cl2, we expect a tetrahedral geometry but as a result of the presence of two lone pairs on each sulphur atom, the molecular geometry is bent. The sulphur is sp3 hybridized.

d) In K4[O3POPO3], each phosphorus atom is in a tetrahedral molecular geometry and is sp3 hybridized.

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3 years ago

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Answer:

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2 years ago

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Answer:

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Explanation:

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3 years ago