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disa [49]
4 years ago
11

How many atoms are in 3.47 moles of C2H2? Please show work.

Chemistry
1 answer:
vaieri [72.5K]4 years ago
8 0

Answer:

2.08×10^24 atoms

Explanation:

set up a mole to atom ratio:

3.47moles 1 mole

------------------ = ----------------------------

x atoms 6.02×10^23 atoms

cross multiply:

3.47 mole × 6.02 × 10^23 = 2.08×10^24 atoms

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What two pieces of evidence did van Helmont use to reach his conclusion
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Explanation:

He weighed silver, dissolved it in acid, and then recovered all the original silver by reacting the solution with copper. He also showed, by using iron to recover the copper, that this displacement of one metal from its salt by using a second metal was not because of transmutation, as many had held.

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2 years ago
Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h
aleksandrvk [35]

Answer:

Concentration = 1.32 m

Boiling point = 83.44^{0}C

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

elevationinboiling point=K_{b}Xmolality

i) For benzene

T-80.1=2.53Xm

T=2.53m+80.1 ....(1)

ii) For carbon tetrachloride

T-76.8=5.03Xm

T=5.03Xm+76.8 ...(2)

Equating the two equations:

5.03Xm+76.8=2.53m+80.1\\m=1.32molal

Putting value of "m" in equation "1"

T=2.53(1.32)+80.1=83.44^{0}C

5 0
3 years ago
Explain to to me about lanthanum
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How do temperature pressure and density change as you move from the outer layer the crust through the mantel to the core? ( 10 p
kupik [55]
This is right
Reduce the concentration of NICO4
6 0
3 years ago
I need to know what is oxidized and what is reduced.
pishuonlain [190]

Answer:

1. Reduction: O₂ ; Oxidation: S

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Determine the oxidation state of each element:

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The oxidation state has decreased; oxygen was reduced.

In SO₂, sulfur acts with +4; oxidation state has increased, so S has been oxidized.

2. Both reactants are at ground state.

In AlF₃  Al has oxidation state of +3 and F, -1

Al increased the oxidation state → oxidation

F decreased the oxidation state → reduction

3. Hydrogen has 0 as oxidation state. In water, H has +1

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