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madreJ [45]
3 years ago
10

Which of the following formulas has the smallest percent

Chemistry
1 answer:
KiRa [710]3 years ago
5 0

Answer: CF4

Explanation:

Calculate the molar mass of each compound. Divide the molar mass of Carbon by the molar mass of each compound, then multiply the answer by 100 to get the percentage.

CF4= 12+(19X 4)

=12+76= 88 g/mol

%C= 12/88 x 100= 13.64%

CO2= 12+(16 X 2)

12+32= 44 G/MOL

%C= 12/44 x 100= 27.3%

CH4= 12+ (1 X4)

=12+4

=16 G/MOL

%C= 12/16  X 100= 75%

C204

(12X2) + (16X4)

24+64

= 88 g/mol

%C= 24/88 x 100

= 27.3%

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Answer:

w= - 1.7173 kJ, q= 1.7173 kJ, q(rev) = 1717.3 J = 1.7173 kJ.

Explanation:

Okay, from the question we are given the information below;

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So, this question is a question from the part of chemistry known as thermodynamics. Therefore, grip yourself we are delving into thermodynamics 'waters' now.

For expansion isothermally; the workdone, w= -nRT ln v2/v1.

Where T= temperature= 25° C = 298 k and R= gas constant.

Therefore; workdone, w = - 1 × 8.314 × 298 × ln(2/1).

Workdone,w= - 1717.32204643. =

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Then, we are to find q. q can be solved by using the first law of thermodynamics, which by mathematical representation is:

∆U= q + w. Where ∆U= change in internal enegy. Since the question is dealing with isothermal expansion, there is this rule that says for an isothermal expansion ∆U = 0.

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q(rev) = 1 × 8.314 × 298 ln (2/1).

q(rev) = 1717.3 J = 1.7173 kJ.

PS: please note the negative signs in the workdone and the positive sign in the q(rev).

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