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yanalaym [24]
3 years ago
12

3 (x - 2) = 7 – (4 - x)​

Mathematics
2 answers:
larisa [96]3 years ago
7 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x=92x=92

Decimal Form:

x=4.5x=4.5

Mixed Number Form:

x=412x=412

-BARSIC- [3]3 years ago
7 0

the answer is x = 9/2

explanation

3 (x - 2) = 7 – (4 - x)

apply the distributive law to 3(x - 2)

to get 3x - 6

simplify 7-(4-x)

3 + x

you now have

3x - 6 = x + 3

add 6 to both sides

<u>-6+6=0</u>   <u>3 + 6 = 9</u>

3x=x+9

subtract x from both sides

<u>3x - x = 2x  </u>   <u>x - x = 0</u>

2x = 9

divide both sides by 2

2x/2 = x    9/2

to get x = 9/2

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How can you represent 100 as an exponential expression with 10 as the base?
Dennis_Churaev [7]

Answer:  

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Step-by-step explanation:

a website to use for more answer:http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U11_L1_T1_text_final.html

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5 0
3 years ago
I have 3 children. Their ages add up to 21, and when multiplied they equal 75. How old are they?
olganol [36]
So represent the ages as x y and z with each being numbers

x+y+z=21
x times y times z=75
this is really tough for elementary school

one way is to find the factors of 75 or the numbers that add up to 75 and trial and error
use whole numbers becuase this is the world of math so


75=1 times 3 times 5 times 5
possible ages are
3,5,5
1,5,15
1,3,25
add them up

3+5+5=13
1+5+15=21 check
1+3+25=29


their ages are 1, 5 and 15
6 0
3 years ago
Read 2 more answers
Jayden’s new puppy weighed 11 1/4 pounds at 4 weeks old. At 16 weeks old, the puppy weighed 1 2/3 times more.
musickatia [10]

Answer:

18.75 or 18 3/4 lbs

Step-by-step explanation:

We just have to multiply 11 1/4 and 1 2/3 to get the product, 18.75 or 18 3/4.

First we have to translate our fractions into decimals:

11.25 (11 1/4) and 1.166667 (1 2/3)

multiply:

11.25 x 1.166667 = 18.75

convert back to fraction:

18 3/4

Hope This helps! Good Luck! If you have any questions please ask me, I would me more than happy to help you understand this method. If you are doing it a different way, I can help with that too.

5 0
3 years ago
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