We are asked to solve for the value of "x" such that when it is added in the original area of the park it will double the area. Let us compute first the area of the original dog park (A1) and the solution is shown below:
Area = Lenght*Width = L*W where L=30 yards and W=20 yards
Area = 30*20
Area = 600 yards squared
Solving for the x, when x is added to both sides which double the area:
A1*2 = (L + 2x)*W
600*2 = (30+2x)*20
1200 / 20 = 30+2x
60 = 30 + 2x
60-30 = 2x
30/2 =x
15 = x
The value of x is 15 yards.
Answer:
a. -5/2
Step-by-step explanation:
I don't know about the first one but the second one is 34.9°. It would be that because are right angles add up to 90° and if you subract 55.1 and 90 it would equal 34.9. But this rule only works on right angles.
2 ways
zero product property
easy way
zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3
m+3=0
m=-3
m=-3 or 3
easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3
B is answer
12x - 8y = -12
6x + 4y = -30
Multiply the 2nd equation by 2, to make the Y coefficients opposite:
6x + 4y = -30 x 2 = 12x + 8y = -60
Now add the two equations:
12x -8y = -12 + 12x +8y = -60
= 24x = -72
Divide bothe sides by 24 to solve for x:
x = -72/24
x = -3
Now replace x with -3 in the first equation to solve for y:
12(-3) - 8y = -12
-36 - 8y = -12
Add 36 to each side:
-8y = 24
Divide both sides by -8 to solve for y:
y = 24 / -8
y = -3
X = -3 and y = -3
(-3,-3)
