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Brut [27]
3 years ago
6

Terrance buys a new car for $20,000. The value of the car depreciates by 15% each year. If f(x) represents the value of the car

after x years, which function represents the car’s value?
Mathematics
2 answers:
Ierofanga [76]3 years ago
6 0
X=13ffychtuu hi guy ignore this
alexandr1967 [171]3 years ago
5 0
$20,000-(0.15*x)=f(x)
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For what value of x does 3^4x – 27x-3?
AveGali [126]

Answer:

x=0,05555555... or x = 3/54 or x= 1/18

Step-by-step explanation:

81x-27x-3

54x=3

8 0
3 years ago
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1(4 – 22); 2 – 2x<br><br> I don’t get this question can someone help me
sertanlavr [38]

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i dont know if this is what u wanted but it wasn't really specified

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3 years ago
There is 3/4 of pizza leftover from the night before. How many 1/8 portiona are there?
lara [203]

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6 0
4 years ago
Abigail has 16 shoes use repeated subtraction to show how many pairs of shoes Abigail has
erik [133]

Hello!

Here is how we solve this question.

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16-2=14

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Hope this helps you with your question.

7 0
3 years ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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