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Marat540 [252]
3 years ago
15

Find the period of the graph shown below A. 4π B. π C. 2π D. 2/3π

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0
A I believe is the answer
mrs_skeptik [129]3 years ago
5 0
I also believe A is the answer.
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A car is 170 inches long. A truck is 75% longer than the car. How long is the truck? *please show an explanation*
Sav [38]

Answer:a

Step-by-step explanation:did

7 0
2 years ago
Help picture attached!!
tigry1 [53]
I think it would be D, because you would divide the 1/8 be 5, giving you 1/40
6 0
3 years ago
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Sophia walked 6 miles in 90 min at Bear Creek Park in Euless, Texas. If she continues at this rate how many miles could walk in
otez555 [7]

Answer:

First you should determine in how many minutes she walks just one mile. For this, you just divide 90:6 and you get 1 mile in 15 minutes. After this, you just divide 60:15 and so you get 4 miles.


7 0
3 years ago
Read 2 more answers
I'll mark brainliest just tell me how to.
IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

3 0
3 years ago
Solve differential equation. Just explain the first 2 steps
lutik1710 [3]
(1) will write us of the following form

\dfrac{dy}{dx}+y^2\sin x=0\\ \\


(2) [do not it need explanation]

\dfrac{dy}{dx}=-y^2\sin x\\ \\


(3) Left place variable "y" and right place, variable "x" like this

\dfrac{dy}{y^2}=-\sin x\, dx\\ \\

(4) Integrate both members 

\displaystyle
\int \dfrac{dy}{y^2}=\int-\sin x\, dx\\ \\

(5) Solve us the integrals

-\dfrac{1}{y}= \cos x+C

(6) Isolate variable "y"

\boxed{y=-\dfrac{1}{\cos x+C}}

C: any cosntant


4 0
2 years ago
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