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stiv31 [10]
3 years ago
13

Julia is evaluating the expression 17(144). If she uses the distributive property to rewrite the expression with friendlier numb

ers, which expression can be a step in her work?

Mathematics
2 answers:
Igoryamba3 years ago
7 0

Answer:

In order to evaluate the given expression 17(144) using the distributive property, Julia would rewrite the expression in friendlier numbers that is:

(10+7)(100+40+4)

Step-by-step explanation:

We are given an expression 17(144) that we have to evaluate let us say without using the calculator.

Sometimes, it is easier to solve a complex problem in multiple steps as the problem gets distributed and the difficulty level lowers for multiple smaller sets.

Julia would rewrite the expression as:

(10+7)(100+40+4)

Then solve it using distribution method as follows:

10(100+40+4)+7(100+40+4)

1000+400+40+700+280+28

= 2448

Ipatiy [6.2K]3 years ago
5 0

The answer to this question is C. 17(100)+17(40)+17(4)

The way i got this answer was that i actually have done this question on a test and Was able to get it for you.

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Answer:

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Step-by-step explanation:

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3 years ago
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

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irina1246 [14]

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