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Mariana [72]
3 years ago
5

Caden rolls two fair number cubes numbered from 1 to 6. He first defines the sample space, as shown below:

Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

Step-by-step explanation:

Sorry I’m am not there

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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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3 years ago
Find the area and perimeter of the algebra titles don't forget your units
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The perimeter of the large square is 24 and the area is 36 units
the perimeter of the small squares are 4 and the areas are 1 unit.
All together the perimeter is 29 and the area is 38.
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2 years ago
Which expression shows twice the sum of 8 and a number n?
IRISSAK [1]
Correct Answer: A. 2(n+8).
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3 years ago
Please help! Correct answer only! This assignment is due today.
Bas_tet [7]

Step-by-step explanation:

Well they made 19 clay, where 12 were vases. That means 7 were not vases. She randomly chooses 16 clay objects, which then also means 3 were left behind. so if the vases are  12/19, which is approximately 63%, then 63% of the objects are vases. Makes sense, right? Well now we need to multiply that by the initial 11 in the question. After all of this work..

Answer: 6.9474 or 6.94736.

Please mark as Brainliest.

6 0
2 years ago
Total power generated by wind worldwide doubles every 3 years. In a particular year, the world wind-generating capacity was abou
NeTakaya
This is a problem of doubling time, the general formula for doubling time is

N = A(2)^( t /d)
where N is the future wind generating capacity in thousand MW
A is the initial wind generating capacity which is 95,000 MW
d is the time it will double, which is 3 years
t is the time in the future in years

N = 95(2)^( t / 3) is the formula for t<span>he continuous growth rate and give a formula for wind generating capacity W W (in thousand megawatts) as a function of t t , the number of years in the future</span>
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